In JEE_Mains 2014 , CBSE asked an problem which doesn't have any correct alternative . And Most surprising thing is tat they Did not give bonus marks to that problem!

So Do you know what is reason behind this ? Is they used some approximation ? If so then what was that ? How we can calculate that approximation !

Problem::

Answer::(Given by CBSE ) JEE_mains have finally said that answer is Option -3 i.e \({ R }^{ 2 }\sqrt { \cfrac { { \rho }_{ w }g }{ 3T } } \) . is correct . They did not give Bonous marks.

Expected Solution::Since no data of bubble is given , So we simply Used that at this time , just before detachment, Surface tension force should balanced buoyant force: \(\displaystyle{(2\pi rT)\sin { \theta } =\left( \cfrac { 4\pi { R }^{ 3 } }{ 3 } -\cfrac { 2\pi { r }^{ 3 } }{ 3 } \right) { \rho }_{ w }g\\ 2\pi rT\times \cfrac { r }{ R } \approx \cfrac { 4\pi { R }^{ 3 } }{ 3 } \times { \rho }_{ w }g\\ \boxed { r\approx { R }^{ 2 }\sqrt { \cfrac { 2{ \rho }_{ w }g }{ 3T } } } }\)

Recently I gave JEE_Mains 2014 paper at home for Practice , and this question Baffles me again !

Please This is open discussion , So Please tell how they approximate answer as option-C ? And what are other different approaches to this Problem ? Please share everything you know about this problem ! Even My teachers says that some-one of CBSE used some approximate and just brute force method to proove this approxiation , Really I want to know about such approximations if it exist !

Thanks!

## Comments

Sort by:

TopNewestThis problem is wrong. It cannot be solved by brute force method. It cannot be solved by any method. We need to know the pressure at bottom of liquid. We can use buoyant force concept if and only if an object is totally surrounded by the fluid. In this case, due to the flat part at the bottom, we have to calculate upward force differently. And to do this, we need the pressure at bottom of liquid.

If any one gets the answer using believable approximations, please share them.

@Deepanshu Gupta @Shashwat Shukla @Mvs Saketh – Raghav Vaidyanathan · 2 years, 2 months ago

Log in to reply

Also, that is why we neglect Air pressure when we calculate weights of real life object, because there is always a layer of air below it and hence net pressure becomes the same as buoyant force hPg, and since for air P is very low(not very dense) , we neglect it, but other wise Air pressure would have a significant effect as it is \(10^{5}\) pascals.

similarly, here it is not very unreasonable to say that there is some water layer at the bottom which we cannot see which pushes it up and net result is buoyant force – Mvs Saketh · 2 years, 2 months ago

Log in to reply

Now think, In this case, the bubble is formed in bottom of vessel. It is said to be attached to it. This means that the boundary of the flat part is physically connected to the vessel, hence creating a boundary between the air inside the bubble and the water outside it. You can also think of it this way: if there is a layer of water(however small) below the bubble, this means that the bubble is fully formed, and thus there is no question of it staying at the bottom, it will immediately rise! – Raghav Vaidyanathan · 2 years, 2 months ago

Log in to reply

@Raghav Vaidyanathan – Shashwat Shukla · 2 years, 2 months ago

Log in to reply

– Ronak Agarwal · 2 years, 2 months ago

Yes, I wanted to say the same thing.Log in to reply

– Raghav Vaidyanathan · 2 years, 2 months ago

Yes, assuming that approximation seems to get us to the answer that the author has posted. Which is not the correct one(according to CBSE).Log in to reply

There is a way to get the answer however. But I don't feel it is justified. It is a matter of definition(and subsequent analysis based strictly on the definition).

It looks like what they mean by a bubble is a surface with two sides. It often happens that CBSE goes with definitions and \(if\) you \(define\) a bubble as an object that has two layers , so as to differentiate it from a drop which has only one layer,

Then the LHS becomes \((4\pi rT)sin\theta\) and we get option C. – Shashwat Shukla · 2 years, 2 months ago

Log in to reply

– Raghav Vaidyanathan · 2 years, 2 months ago

Yeah, I thought we might be able to understand what they did if we considered the actual case and then go about doing approximations. And yes, your explanation for the missing factor of \(2\) is plausible. They might have done the same.Log in to reply

Yes May be if we just want to match the option-c , then may be you are correct , May be Possible they unnesseseerily assume bubble has two layers!Yes which can't be stable when we are heating , is they ? But what about If we Just want to do this question from very basic ? I mean by doing some calculation of Pressure at the circular bottom ? or Can we do by using Ideal behaviour of air inside bubble ? @Shashwat Shukla @Mvs Saketh @Ronak Agarwal @Raghav Vaidyanathan – Deepanshu Gupta · 2 years, 2 months ago

Log in to reply

I too doubt it now, you are right, the only logical way to solve this would be to deal with the air inside the bubble and find its pressure,

@Ronak Agarwal help? – Mvs Saketh · 2 years, 2 months ago

Log in to reply

– Pranjal Jain · 2 years, 2 months ago

Well, as far as I remember, bonus marks were given for this question later. (After corrections)Log in to reply

Set E Question Paper Q-28 physics

No , I know Because I give that exam , and I did not get marks! SeeSee This official answer

– Deepanshu Gupta · 2 years, 2 months agoLog in to reply

It looks like what they mean by a bubble is a surface with two sides.

Then the LHS becomes \((4\pi rT)sin\theta\) and we get option C.

But this is definitely incorrect reasoning and the question is wrong, I guess. – Shashwat Shukla · 2 years, 2 months ago

Log in to reply

– Deepanshu Gupta · 2 years, 2 months ago

ahh , But bro can you please explain what is mechanism of This Bubble formation ? I don't think that two layers will form on heating ? Please discussLog in to reply

But the thing is, it often happens that CBSE goes with definitions and \(if\) you \(define\) a bubble as an object that has two layers , so as to differentiate it from a drop which has only one layer, then maybe they expected us to go by this definition of a bubble. – Shashwat Shukla · 2 years, 2 months ago

Log in to reply

This question is wrong, it is given in FIITJEE to be wrong as well, i have seen it before i thought marks were given for that . and no approximation can justify that – Mvs Saketh · 2 years, 2 months ago

Log in to reply

And My Sir Say's they brutly Proved it that by some approximationS , I know they are wrong , but due to their prestige they unnecesserry proved that ! I don't know how , Even It is difficult for me to digest ! – Deepanshu Gupta · 2 years, 2 months ago

Log in to reply

In my view they should give it as bonus. – Ronak Agarwal · 2 years, 2 months ago

Log in to reply

And Yes I agree that they should give , but unfortunately they didn't! – Deepanshu Gupta · 2 years, 2 months ago

Log in to reply

– Ronak Agarwal · 2 years, 2 months ago

You already gave JEE-Mains 2014, so why did you give it again , also you got 322 in mains you gave previous year no.Log in to reply

Mains Paper , to find which topics I need to be practise and revise , Since It is impossible to give revise whole course ! And Actualy i did not give only this year paper , I give 2013 and all 4 of online 2013 paper too ! And Now I gave 2014mains and , my next target is to give all 4 Mains 2014 Online Papers.So It is just for finding what topics are need to be revise ! that's why I gave that , also I want to anaylise my Last year mistakes So I gave it. – Deepanshu Gupta · 2 years, 2 months ago

Log in to reply

@Deepanshu Gupta – Mvs Saketh · 2 years, 2 months ago

can you tell me where you got online jee main papers? for practiceLog in to reply

For JEE

Mains 2014 Question Papers click here JEEmains2014For JEE

mains 2013 question Papersclick here JEEmains2013after cliking on second link(JEE

Mains 2013) , scroll down the page , and you will find a red Mark , click on that and you will find one another link after again scrolling down the page , which is written after 4 dates of JEEMAINS 2013 ! click on that and download all 4 papers ! Hopes This Helps ! @Mvs Saketh – Deepanshu Gupta · 2 years, 2 months agoLog in to reply

– Ronak Agarwal · 2 years, 2 months ago

So the marks you posted were the marks you got when you actually gave JEE Mains Last Year.Log in to reply

– Deepanshu Gupta · 2 years, 2 months ago

No, no I got worst marks in last year, that was horrible experience! And this marks was got a day before when I gave it again at home !Log in to reply

– Ronak Agarwal · 2 years, 2 months ago

The same accuracy problem pestures me also, most of times I don't read questions carefully, misread words , misinterpretations and all, how you improved your accuracy, does revising theory helps, or more practicing questions, or may be give practice papers.Log in to reply

mains paper 5 of 2013 and 5 of 2014 (including online and offline) , Also AIEEE 2012 and AIEEE 2011 Paper are also on same JEEMains Pattern . So I'am reguarly giving one Paper each day and then analylyse my mistakes and analyse what topics need's to be revise . Since It is impossible to revise notes, atleast maths and physics did not needs reading of theory notes ! But what you think ? Should still we should atleast take a qiuck look on notes ? and what else ? – Deepanshu Gupta · 2 years, 2 months agoLog in to reply

– Ronak Agarwal · 2 years, 2 months ago

I got 320 in mains, chemistry took me down , Physics-110,Maths-115,Chemistry-95Log in to reply

– Mvs Saketh · 2 years, 2 months ago

Indeed, they should have looked into it , unfortunately they did'ntLog in to reply

@Sudeep Salgia @Karthik Kannan @jatin yadav will you guys please put some light on it ? And all other freinds Please Discuss this ! Thanks! – Deepanshu Gupta · 2 years, 2 months ago

Log in to reply