×

# jmo question

Find a number which when divided by 10 leaves remainder 9, when divided by 8 leaves remainder 7, etc. down to where when divided by 2, it leaves remainder 1.

Note by Ayushi Gupta
3 years, 4 months ago

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold
- bulleted- list
• bulleted
• list
1. numbered2. list
1. numbered
2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in $$...$$ or $...$ to ensure proper formatting.
2 \times 3 $$2 \times 3$$
2^{34} $$2^{34}$$
a_{i-1} $$a_{i-1}$$
\frac{2}{3} $$\frac{2}{3}$$
\sqrt{2} $$\sqrt{2}$$
\sum_{i=1}^3 $$\sum_{i=1}^3$$
\sin \theta $$\sin \theta$$
\boxed{123} $$\boxed{123}$$

Sort by:

Let the no be A A = 10.b -1 A= 8.c -1 A= 6.d -1 A= 4e -1 A= 2f -1 Taking lcm of 10 , 8 , 6, 4, 2 we will get 120 120-1 =119

- 2 years, 4 months ago

119

- 2 years, 5 months ago

2519 is the smallest of such no.s

- 2 years, 6 months ago

839

- 3 years, 3 months ago

119

- 3 years, 4 months ago