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Find with proof, all integer values of \(k\) such that \(2^k=k^2\)

Note by Aditya Raut 2 years, 8 months ago

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When k>4, \(2^k>k^2\) by an easy induction.That leaves k=0,2.,4 – Bogdan Simeonov · 2 years, 8 months ago

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@Bogdan Simeonov – Wrong. Giving "0" will give you "0" marks too :P \(2^0 =1 , 0^2=0\) and \(1\neq 0\) – Aditya Raut · 2 years, 8 months ago

@Aditya Raut – Eh, sorry for that lol.Doesnt matter because it's the same solution – Bogdan Simeonov · 2 years, 8 months ago

2, 4 are the integers req. – Rishabh Tiwari · 1 year ago

2.4 – Manar Mohamed · 2 years, 8 months ago

@Manar Mohamed – Can you prove it? – Colin Carmody · 2 years ago

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## Comments

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TopNewestWhen k>4, \(2^k>k^2\) by an easy induction.That leaves k=0,2.,4 – Bogdan Simeonov · 2 years, 8 months ago

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– Aditya Raut · 2 years, 8 months ago

Wrong. Giving "0" will give you "0" marks too :P \(2^0 =1 , 0^2=0\) and \(1\neq 0\)Log in to reply

– Bogdan Simeonov · 2 years, 8 months ago

Eh, sorry for that lol.Doesnt matter because it's the same solutionLog in to reply

2, 4 are the integers req. – Rishabh Tiwari · 1 year ago

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2.4 – Manar Mohamed · 2 years, 8 months ago

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– Colin Carmody · 2 years ago

Can you prove it?Log in to reply