# Can anyone explain how is it wrong??

Note by Shuvayan Ghosh Dastidar
4 years, 4 months ago

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When $$x^3 - x^2 = x^2(x - 1)$$ you divided by zero.

- 4 years, 4 months ago

$$(x-1)$$ is equal to $$-1$$, not $$0$$. This is because you multiplied the $$x^3$$ factor to get $$0$$, meaning that $$1\ne0$$.

- 4 years, 4 months ago

till x^2(x-1) =0 everything is right but on next step there is mistake. if ab=0 , a or b is 0 .Here a=x^2,b=(x-1).We already have a=0 which results in (x-1) may or may not equal to zero.To make the equation correct,(x-1) not equal to zero

- 4 years, 4 months ago