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Just for fun!!!

Is it really possible that 1=0??!!!

well, let's try-

let x=0

x^2=0.0=0

x^3=0.0.0=0

Now,

x^3-x^2=0-0=0

x^2(x-1)=0

Or,x-1=0

Or,x=1!!!

Can anyone explain how is it wrong??

Note by Shuvayan Ghosh Dastidar
3 years, 3 months ago

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When \(x^3 - x^2 = x^2(x - 1)\) you divided by zero. Sharky Kesa · 3 years, 3 months ago

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\((x-1)\) is equal to \(-1\), not \(0\). This is because you multiplied the \(x^3\) factor to get \(0\), meaning that \(1\ne0\). Michael Diao · 3 years, 3 months ago

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till x^2(x-1) =0 everything is right but on next step there is mistake. if ab=0 , a or b is 0 .Here a=x^2,b=(x-1).We already have a=0 which results in (x-1) may or may not equal to zero.To make the equation correct,(x-1) not equal to zero Shaheed Vh · 3 years, 3 months ago

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