A motor car is going due north at a speed of 50km/h.it makes a 90degree left turn without changing the speed.The change in the velocity of the car is about

When the car is going north, the velocity is +50j (assuming up is +j, right is +i in vector coordinates). When car takes left turn, it is moving west, so the velocity is -50i. Change is velocity is final velocity - initial velocity = (-50i - 50j)km/hr.

This should be your final answer. You have to consider direction also, since change in "velocity" is asked.

## Comments

Sort by:

TopNewestWhen the car is going north, the velocity is +50j (assuming up is +j, right is +i in vector coordinates). When car takes left turn, it is moving west, so the velocity is -50i. Change is velocity is final velocity - initial velocity = (-50i - 50j)km/hr.

This should be your final answer. You have to consider direction also, since change in "velocity" is asked.

Log in to reply

0

Log in to reply

0

Log in to reply