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# KVPY 2014 problem

This problem was asked in KVPY 2014 held on 2nd November SA stream

The value of -

$$\sum _{ n=0 }^{ 1947 }{ \frac { 1 }{ { 2 }^{ n }+\sqrt { { 2 }^{ 1947 } } } }$$

is equal to-

A. $$\frac { 487 }{ \sqrt { { 2 }^{ 1945 } } }$$

B. $$\frac { 1946 }{ \sqrt { { 2 }^{ 1947 } } }$$

C. $$\frac { 1947 }{ \sqrt { { 2 }^{ 1947 } } }$$

D. $$\frac { 1948 }{ \sqrt { { 2 }^{ 1947 } } }$$

Note by Karthik Sharma
2 years, 2 months ago

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@Karthik Sharma Combine the first and the last term, then the 2nd and 2nd last.. See what happens · 2 years, 2 months ago

Oh! yes got it now. Its 'A'. · 2 years, 2 months ago

As we devide same digits we get ans. 1 what happen in this 0/0. · 2 years, 2 months ago