This problem was asked in KVPY 2014 held on 2nd November SA stream

The value of -

\(\sum _{ n=0 }^{ 1947 }{ \frac { 1 }{ { 2 }^{ n }+\sqrt { { 2 }^{ 1947 } } } } \)

is equal to-

A. \(\frac { 487 }{ \sqrt { { 2 }^{ 1945 } } } \)

B. \(\frac { 1946 }{ \sqrt { { 2 }^{ 1947 } } }\)

C. \(\frac { 1947 }{ \sqrt { { 2 }^{ 1947 } } }\)

D. \(\frac { 1948 }{ \sqrt { { 2 }^{ 1947 } } }\)

## Comments

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TopNewest@Karthik Sharma Combine the first and the last term, then the 2nd and 2nd last.. See what happens – Pratik Shastri · 2 years, 4 months ago

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– Karthik Sharma · 2 years, 4 months ago

Oh! yes got it now. Its 'A'.Log in to reply

As we devide same digits we get ans. 1 what happen in this 0/0. – Sahil Kumar · 2 years, 4 months ago

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DUDE APKO NI PTA – Navdeep Nainwal · 2 years, 4 months ago

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