I am a 15 years old boy from Bangladesh,who has always loved doing GEOMETRY and probably would be,always.Actually,i am quite insistent to find the solution of any problem.Even I solved some of them after trying several months continuously!! However,here I would like to introduce a Geometry Problem that I have been trying for about 3 months but haven't found much clue.WHY DON'T SOLVE TOGETHER?!

**In the diagram above,▲ADB is a right angled triangle,where ∠ADB is right angle.E is a point on DB.EF is perpendicular to AB.AE meets the circumcircle of ▲ADB at H and FH meets DB at G.Given that. DE=5,EG=3.Find the value of BG.**

All I have found is some similar triangles, even adding something new seemed more complex.I will of course share ,what I have found this far.lets discuss together! You can share any of your thoughts regarding the problem and ask any question freely!! HOPE TO TALK TO YOU SOON! ;))

No vote yet

1 vote

$</code> ... <code>$</code>...<code>."> Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in $</span> ... <span>$ or $</span> ... <span>$ to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestBG=12

Hint: Drop the altitude from D onto AB and extend to intersect with circumcircle. Compare with the point of intersection of FH with the circumcircle(on the other side).

Log in to reply

OH MY GOD!!! You even don't know,how much emotions I gathered around this math.I thought for a moment,if I would be able to solve that ever or not.THANK YOU SO MUCH!!! I tried by the method, and found that they both meet at the same point.then I worked with the similar triangles!! again,than you!! Your favor truly means a lot to me. gonna follow you now. ;))

Log in to reply