There are 5 letters and 5 envelopes and for each letter there is only one right envelope present.In how many ways can one put the letters in the envelopes so that no letter is in the right envelope? I would be really glad to get a hint about its solution.

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TopNewestThanks for the reply. – Sazzad Sayyed · 3 years, 3 months ago

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ya it is the no. of derangements – Sitesh Pattanaik · 3 years, 4 months ago

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– Bhargav Das · 3 years, 3 months ago

I think the answer is 44.Log in to reply

Hi; You want the number of derangements. This link covers it all.

link – Bobbym None · 3 years, 4 months ago

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