Light and Time... doesn't match

Light is emitted by matter which is at a speed lower than cc. Also, Light travels only at a speed c=299792458c=299792458 m/s. Also, Acceleration a=ΔvΔta=\frac{\Delta v}{\Delta t}. as Light can only travel at cc, light must achieve cc in Δt=0\Delta t=0. if a=Δv0a=\frac{\Delta v}{0} then a=a=\infty.Will it happen in this universe? or is there any medium in this universe? I request everyone to comment on this... Please Don't Ignore... Even if yours or my answer is wrong,comment on this...

Note by Fahad Shihab
6 years ago

No vote yet
1 vote

  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

  • Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
  • Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
  • Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
  • Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

Sort by:

Top Newest

Your assumption that Δt=0\Delta t=0 is right but you also assume that Δv0\Delta v \neq 0 which is not right. Actually Δv\Delta v is also equal to 00. This is because the initial and final speed are same and equal to cc.

Shubham Srivastava - 6 years ago

Log in to reply

how? Light is emitted by matter which is travelling at speeds below cc. So, if it wants to go at cc, a change of velocity must occur. so,Δv0\Delta v\neq0.

Fahad Shihab - 6 years ago

Log in to reply

Rule of Mathematics, In Shape ab\frac{a}{b} , with b \neq 0, so there exists this possibility ! Δ\Deltatt \neq 0

Gabriel Merces - 6 years ago

Log in to reply

in relativity, it is said that light can't travel at a speed lower than cc

Fahad Shihab - 6 years ago

Log in to reply

It has to be a time for less than Be, After All Denominator must be \neq of 0

Alex Dias - 6 years ago

Log in to reply

@Alex Dias that's why i am saying that even light can travel at speeds lower than cc

Fahad Shihab - 6 years ago

Log in to reply

Photons can only travel at a speed of cc in which beforehand, for instance when emitted from a atom; they simply didn't exist in the form of a photon. Photons theoretically have no mass as they do not interact with the Higgs field; hence cannot be accelerated.

Joel Jablonski - 6 years ago

Log in to reply

OK. so, if it didn't exist in the form of a photon, it must have a travelling speed, that is c=299792458ms1c=299792458ms^{-1} and according to my knowledge, a=ΔvΔta=\frac{\Delta v}{\Delta t} as acceleration is a funcion of time, not mass. So, even if its mass is zero, it should have an acceleration. Can't it be?

Fahad Shihab - 6 years ago

Log in to reply

I understand where you are coming from and I agree that acceleration is a function of the time, but it is only a representation. When the time 0 the velocity is already c and it did not start from a velocity of 0, it simply didn't exist in the form of a photon as I previously said. The travelling speed that you are talking about was just a form of energy that was suddenly converted into a photon, it didn't exactly have a 'speed' more like a potential.

The acceleration of a particle is not determined by the time, it is determined by its mass or the Higgs field. I haven't studied general relativity in depth though seeming as the photon does not interact with the Higgs field, it can not change its speed. Hence, the acceleration of the photon is a=ΔvΔta=\frac{Δv}{Δt} where change in velocity is 0, hence acceleration must always be 0 no matter what time, even at t=0.

Joel Jablonski - 6 years ago

Log in to reply

@Joel Jablonski So, physically, light isn't visible to us. That means it is a wave and photons are imaginary. Then what is the reason for self propagation of light?

Fahad Shihab - 6 years ago

Log in to reply

Now another news... check this out!

Fahad Shihab - 6 years ago

Log in to reply

cc, is the speed of light in a vaccum, light doesn't slow down (de-accelerate), it just travels slower in a different medium. End of story.

Yong See Foo - 6 years ago

Log in to reply

i am talking about light in a vacuum. Not mediums.

Fahad Shihab - 6 years ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...