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# Light and Time... doesn't match

Light is emitted by matter which is at a speed lower than $$c$$. Also, Light travels only at a speed $$c=299792458$$ m/s. Also, Acceleration $$a=\frac{\Delta v}{\Delta t}$$. as Light can only travel at $$c$$, light must achieve $$c$$ in $$\Delta t=0$$. if $$a=\frac{\Delta v}{0}$$ then $$a=\infty$$.Will it happen in this universe? or is there any medium in this universe? I request everyone to comment on this... Please Don't Ignore... Even if yours or my answer is wrong,comment on this...

4 years, 3 months ago

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Your assumption that $$\Delta t=0$$ is right but you also assume that $$\Delta v \neq 0$$ which is not right. Actually $$\Delta v$$ is also equal to $$0$$. This is because the initial and final speed are same and equal to $$c$$.

- 4 years, 3 months ago

how? Light is emitted by matter which is travelling at speeds below $$c$$. So, if it wants to go at $$c$$, a change of velocity must occur. so,$$\Delta v\neq0$$.

- 4 years, 3 months ago

$$c$$, is the speed of light in a vaccum, light doesn't slow down (de-accelerate), it just travels slower in a different medium. End of story.

- 4 years, 3 months ago

i am talking about light in a vacuum. Not mediums.

- 4 years, 3 months ago

Now another news... check this out!

- 4 years, 3 months ago

Photons can only travel at a speed of $$c$$ in which beforehand, for instance when emitted from a atom; they simply didn't exist in the form of a photon. Photons theoretically have no mass as they do not interact with the Higgs field; hence cannot be accelerated.

- 4 years, 3 months ago

OK. so, if it didn't exist in the form of a photon, it must have a travelling speed, that is $$c=299792458ms^{-1}$$ and according to my knowledge, $$a=\frac{\Delta v}{\Delta t}$$ as acceleration is a funcion of time, not mass. So, even if its mass is zero, it should have an acceleration. Can't it be?

- 4 years, 3 months ago

I understand where you are coming from and I agree that acceleration is a function of the time, but it is only a representation. When the time 0 the velocity is already c and it did not start from a velocity of 0, it simply didn't exist in the form of a photon as I previously said. The travelling speed that you are talking about was just a form of energy that was suddenly converted into a photon, it didn't exactly have a 'speed' more like a potential.

The acceleration of a particle is not determined by the time, it is determined by its mass or the Higgs field. I haven't studied general relativity in depth though seeming as the photon does not interact with the Higgs field, it can not change its speed. Hence, the acceleration of the photon is $$a=\frac{Δv}{Δt}$$ where change in velocity is 0, hence acceleration must always be 0 no matter what time, even at t=0.

- 4 years, 3 months ago

So, physically, light isn't visible to us. That means it is a wave and photons are imaginary. Then what is the reason for self propagation of light?

- 4 years, 3 months ago

Rule of Mathematics, In Shape $$\frac{a}{b}$$ , with b $$\neq$$ 0, so there exists this possibility ! $$\Delta$$$$t$$ $$\neq$$ 0

- 4 years, 3 months ago

in relativity, it is said that light can't travel at a speed lower than $$c$$

- 4 years, 3 months ago

It has to be a time for less than Be, After All Denominator must be $$\neq$$ of 0

- 4 years, 3 months ago

that's why i am saying that even light can travel at speeds lower than $$c$$

- 4 years, 3 months ago