take tanx common from each of the terms( i mean those brackets).
then take 10^{tanx} common from all the terms and it gets divided with 9^{tanx} in the denominator leaving tanx in the numerator
something /tanx tends to 0 because tanx tends to infinity
so the inside part will be adding up to 20 making it 20*tanx
then it will be zero
my answer does not tally with the above one please tell me what is wrong.

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## Comments

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TopNewestTaking the LCM and then considering the expansion of all the terms

Now first 9 terms of expansion will result a polynomial in tanx of degree 8 or lower.

Hence it would tend to zero as x»π/2 Hence writing the last two terms of the expansion

We would get the limit basically as the coefficient of (tanx)^9 in the numerator as =10C9

[1+2+3+ …. 20] = 10[20*21/2] = 2100Log in to reply

Thanks... It didnt strike me...

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Where did you get such horrible problem from?

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"Horrible" in what sense???? Btw i got it in a test..could'nt solve it..

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No way this problem is horrible.

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You mean easy??

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take tanx common from each of the terms( i mean those brackets). then take 10^{tanx} common from all the terms and it gets divided with 9^{tanx} in the denominator leaving tanx in the numerator something /tanx tends to 0 because tanx tends to infinity so the inside part will be adding up to 20 making it 20*tanx then it will be zero my answer does not tally with the above one please tell me what is wrong.

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