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I am almost "psychic".
Take any real, non-zero number,
Take that number's square,
Add Twice the original number,
Add 1,
Take the square root(positive only),
Subtract your original number,
Multiply by 1336,
Add 1. You are thinking of..... 1337 :D

Note by Brian Wang
2 years ago

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1 vote

  Easy Math Editor

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**bold** or __bold__ bold

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[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

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# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

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\(1+1336(\sqrt{x^2+2x+1}-x) = 1+1336(|x+1|-x) = 1337\)

Kay Xspre - 2 years ago

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Shhhhhhh

Brian Wang - 2 years ago

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