Whats possibly wrong in this equation.. have seen these stuffs when I was small but why isn't it correct ?

9 = (-3)^2

9 = (3)^2

accordingly, (-3)^2 = (3)^2 => -3 = 3 => 6 = 0 and hence infinite solutions arise after this showing n=0 for all n belonging to real numbers. :P

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## Comments

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TopNewestthe fallacy here is that the rule of taking the root of an equation only holds true when both numbers are positive, which -3 is not. Therefore, algebra continues to hold true.

This is a useful website for these types of problems http://en.wikipedia.org/wiki/Mathematical_fallacy

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Lol. Wikipedia is a "useful" site.

only americansLog in to reply

We know that while taking roots we have to take modulus on both the sides i.e. (in this problem) after (-3)^ 2 =(3)^ 2

|-3| =|3|

which gives us 3=3 which is always true

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When taking square root...be careful to take modulus on both sides...which gives u 3=3!!

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