×

# MatheMagic !!!

Two boys went to a book shop and purchased a book which costs $50. They paid$25 each for the book and left the store. When the store manager went to the cashier, he found that they have taken $5 extra from them. So, the actual cost of the book was$45. The manager gave $5 to a worker out there to return it to those boys. Let's make it more interesting, the worker was a bit greedy, he took$2 from it and returned $3 to the boys. They distributed$1.5 and $1.5 each and thought that they have paid$25 - $1.5 =$23.5 each for the book. Here comes the problem, Now, we all (I mean those who are reading this thread) know that the boys paid $23.5 +$23.5 = $47 and the worker have only$2 which adds up to $49. Where do you think$1 lost in the process ?

Note by Abhishek Kumar
4 years, 4 months ago

Sort by:

you are supposed to add $3 to$47 because the worker's $2 is counted in the$47

- 4 years, 4 months ago

u r talking about cost price in the first half and then reverse calculating it by sell price in the second half.so its obvious why they are not adding up

- 4 years, 4 months ago

that is subtract $3 from$50 then subtract $2 thus it adds up - 4 years, 4 months ago Log in to reply do like this they each have paid$23.5 so in total $47.now waht u r duin rong is that they actually bought the book for$45(after gettin money back) but they paid $47 because the cashier cheated$2 on them i.e $47 -$2

- 4 years, 4 months ago