To get the area of the minor segment AB , you'll first calculate the area of the sector AOB using the formula that i had provided earlier . Now subtract the area of the triangle from the area of the sector to get the area of the segment .

If you want to get the area of the major segment , then you'll have to subtract that area from the area of the circle .

$</code> ... <code>$</code>...<code>."> Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in $</span> ... <span>$ or $</span> ... <span>$ to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

Sort by:

TopNewestYeah , exactly ! I don't understand why there are people out there who can't understand this simple fact .

Log in to reply

hi there. are you good at solid mensuration?

Log in to reply

You mean something on the lines of 3D geometry ?

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

smart-_-There are many smarter people out here on B'ant . The list is endless !

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

Log in to reply

$\ddot\smile$

ThanksLog in to reply

Did you mean the following formula ?

$\text{Area of sector} = \dfrac{\theta}{2\pi} \pi r^{2}$

And likewise the formula for segment can be got by subtracting it from the triangle formed by the chord with the radii .

I am confused by your comment since a segment is a segment in both 2D as well as 3D .

Log in to reply

Log in to reply

Log in to reply

To get the area of the minor segment AB , you'll first calculate the area of the sector AOB using the formula that i had provided earlier . Now subtract the area of the triangle from the area of the sector to get the area of the segment .

If you want to get the area of the major segment , then you'll have to subtract that area from the area of the circle .

Log in to reply