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can anyone solve this problem for me? (cos36 + isin36)^{36}

Note by Akash Sinha
3 years, 6 months ago

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(cos36 + isin36)^{36}

= (e^i36)^(36) = (e^i1296) = (cos1296 + isin1296) = (cos216 + isin216) = (-cos36 - isin36) = {-}(cos36 + isin36) Rushi Rokad · 3 years, 6 months ago

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