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Find the sum of all integers S that are less than 1000 and equal to UNDER ROOT ( A!+1) for some positive integer A.

Note by Akash Gupta 4 years, 10 months ago

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2 \times 3

2^{34}

a_{i-1}

\frac{2}{3}

\sqrt{2}

\sum_{i=1}^3

\sin \theta

\boxed{123}

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Sorry, there was an error posting the answer, as the question you have asked is a challenge question. Please do not resort to cheating while answering questions on brilliant.

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I HAVE TAKEN IT FROM THE BOOK IIT EXPLORER

But I answered the same question 4 days back on brilliant.

@Aditya Parson – You can do this sum by hand itself, just calculate for A=1 to 10. And see for which values you get an integer for n!+1,

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Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

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TopNewestSorry, there was an error posting the answer, as the question you have asked is a challenge question. Please do not resort to cheating while answering questions on brilliant.

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I HAVE TAKEN IT FROM THE BOOK IIT EXPLORER

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But I answered the same question 4 days back on brilliant.

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