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Let's prove that angle a+angle b+angle c=90°
It is obvious that angle c=45°(it is the diagonal of a square) Next we evaluate the segments. Let the shorter side be a and the longer 3a(we know it from the task) it is easy to see that the first segment is a×sqrt2 next one a×sqrt5 and the last axsqrt10. Now we'll prove that they are similar(the triangles) a×sqrt5/a×sqrt2=a×sqrt10/a×sqrt5 since 2 pairs and proportiante they are similar so their angles must be the same from all the we get that angle a+angle b=45° which was to be proven

Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

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## Comments

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TopNewestDo you like carrots?

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i like carrots,the sound of the crunch helps in concentrating.

BTW, what is the reason that you ask everyone about their affinity towards carrots?

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No

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I got 0.26 incorrect

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aise hi kara kya

2TSinx=u(l1)g ?

and T+u(l2)g sinx=u(l2)g Cosx k

where l1 is hanging part and l2 is part in contact. required value is maximum of (l1)/2(l2) which comes out to be (sinxcosx-sin^2x)?

u= linear mass density k is friction coefficient

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Rectified my calculation mistake .

Got the answer correct

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Ajeeb sa question Ye kya question hai ???? Ye bad habit hai aise question nhi krte bhaskar bhaiyaa

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@Bhaskar Kumawat @Deepanshu Vijay @Harshit Jain @Shivam Mittal We can talk here!

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Bhaskar I got the answer of that question. check your method again

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@Harshit Jain Jain tere waale recurrence question ka answer to incorrect aa raha hai

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But the answer should be changed

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Harshit tu recurrence ko edit kr uska answer 600/574 aa rha tha to usko 300/287 to bhi likh sakte hian

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@Bhaskar Kumawat Activity Set mein question daalo.

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Trying to solve this

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Getting answer :0.3. Not correct

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@Harshit Jain Check This

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Abhi to kuch kiya hi nahin

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Try the problem I tried below

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I almost solved it. Still got one try

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@Harshit Jain @Deepanshu Vijay Kahan Pe ho tum dono

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@Harshit Jain Question

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Kahan gae sab

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Let's prove that angle a+angle b+angle c=90° It is obvious that angle c=45°(it is the diagonal of a square) Next we evaluate the segments. Let the shorter side be a and the longer 3a(we know it from the task) it is easy to see that the first segment is a×sqrt2 next one a×sqrt5 and the last axsqrt10. Now we'll prove that they are similar(the triangles) a×sqrt5/a×sqrt2=a×sqrt10/a×sqrt5 since 2 pairs and proportiante they are similar so their angles must be the same from all the we get that angle a+angle b=45° which was to be proven

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Try This : https://projecteuler.net

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@Bhaskar Kumawat wo tum konsa game khelte ho spacecreft wala

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chup chap padh rahe honge

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Harshit Ne bola tha ki wo brilliant hi chala rha hai

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