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Hello everyone ,

I've just learnt the "Method of differences" and I'm really fascinated by the method !

Can somebody help me out how can we find the **original polynomial** \( f(x) \) ,

[ For example \( f(x) \) of the form \( f(x)= ax^n + bx^{n-1} + \dots \) ]

after drawing the **difference table** (i.e. after finding the **values** of \( f(a) , D_1(a) \dots \) ) ?

Do elaborate 'cause I don't know much about Binomials .

Thank you.

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TopNewestI'm encourage you to read through Worked Example 1, and do the (*) exercise, which gives you the answer. – Calvin Lin Staff · 3 years, 9 months ago

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Please help , Thank you ! – Priyansh Sangule · 3 years, 9 months ago

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Are you talking about the values of \(f(n)\), or the closed form? – Tim Vermeulen · 3 years, 9 months ago

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– Priyansh Sangule · 3 years, 9 months ago

The original polynomial of the form \( f(x) = ax^n + bx^{n-1} + \dots \)Log in to reply

– Tim Vermeulen · 3 years, 9 months ago

Okay. Could you give an example of such a table? I'd be happy to help you find the original polynomial.Log in to reply

A

cubicpolynomial \(f(x)\) has the following values -\(f(1)=13 ; f(2)=32 ; f(3)=69 ; f(4)=130 \)

Find \( f(x) \) .

So for this , first of all , I draw a

difference table\( \begin{matrix} n & f(n) & D_1(n) & D_2(n) & D_3(n) & \dots \\ 1 & 13 & 19 & 18 & 6 & \dots \\ 2 & 32 & 37 & 24 & \dots \\ 3 & 69 & 61 & \dots \\ 4 & 130 & \dots \\ \vdots \end{matrix} \)

Now , at this point I run into trouble - that how can I find the polynomial of the form \( f(x) = ax^n + bx^{n-1} + \dots \)

Please help and do

elaborate!Thank you – Priyansh Sangule · 3 years, 9 months ago

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@Sreejato Bhattacharya @Yan Yau Cheng @Aditya Raut @Tim Vermeulen @Bhargav Das @Calvin Lin

I need help guys :) – Priyansh Sangule · 2 years, 10 months ago

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