nine gallons are drawn from a cask full of wine; it is then filled with water,then nine gallons of mixture are drawn,and the cask is filled again with water.If the quantity of wine now in the cask be to the quantity of water in it as 16 to 9,how much does the cask hold?

guys i want you to work out simplest solution possible as i am not that smart........!

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TopNewestAssume cask is x gallons. Therefore, x-9 is drawn first time. Subsequently, it is drawn out 9 gallons for the second time. This can be represented by (x-9)^2/x^2= 16/25, solve for x. x is 45 gallons.

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50 gallons

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i 'll be glad if u show me complete procedure

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