# Modern physics

A particle moves in a closed orbit around the origin due to a force which directed towards the origin.The de-broglie wavelength of the particle vaies cyclically between two values ${ \lambda }_{ 1 }\& { \lambda }_{ 2 }\quad ({ \lambda }_{ 1 }>{ \lambda }_{ 2 })$ . Which of the following statement(s) are true ?

1)- at ${ \lambda }_{ 1 }$ it is closest to origin .

2)- at ${ \lambda }_{ 2 }$ it is closest to origin .

3)- the kinetic energy of the particle is inversely proportional to the wavelength .

4)- Particle moves in Circular orbits .

5)-Particle moves in Elliptical orbits.

6)-the angular momentum of the Particle is inversely proportional to the wavelength .

Note by Nishu Sharma
5 years ago

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## Comments

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This is the original problem:

11.13 A particle moves in a closed orbit around the origin, due to a force which is directed towards the origin. The de Broglie wavelength of the particle varies cyclically between two values λ1, λ2 with λ1>λ2. Which of the following statement are true?

(a) The particle could be moving in a circular orbit with origin as centre

(b) The particle could be moving in an elliptic orbit with origin as its focus.

(c) When the de Broglie wave length is λ1, the particle is nearer the origin than when its value is λ2.

(d) When the de Broglic wavelength is λ2, the particle is nearer the origin than when its value is λ1.

This problem is perfect and doesn't leave room for the ambiguity that Ronak mentioned.

- 5 years ago

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- 5 years ago

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Clearly particle is revolving in a elliptical orbit since the de broglie wavelength is changing between two values.

When wavelength is more means velocity is less hence particle is at farther position ( conserve angular momentum because of central force)

Kinetic energy is inversely proportional to square of wavelength.

- 5 years ago

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@Ronak Agarwal @Nishant Rai please do reply , I'm waiting

- 5 years ago

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Sorry But I don't able to digest , that It is moving in elliptical orbit . Can you please Explain how It can prooved ?

- 5 years ago

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Oh sorry sorry we can't say it is an elliptical orbit, I assumed it to be a central force following inverse square law. But it is not.

- 5 years ago

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There is nothing to think further, all my other statement are correct also we can't say which kind of orbit it is.

Also one more point angular momentum is constant, hence it can't be proportional to anything.

- 5 years ago

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Sorry But I have answer as Elliptical orbit's .. This was the main problem of mine ... I can't conclude anything .. that's why i posted here...

- 5 years ago

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This simply means the question is incorrect they forgot to mention it as inverse square force. Have you tried the problem Magnet in a copper tube. Also I have corrected the link.

- 5 years ago

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i tried Magnet Falling in a Copper Tube... beautiful problem. It took some time to analyse the situation.

- 5 years ago

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ohh but yes it is not neccessery ..... So would you tell , what are you thinking now ? I'am really want to solve this , I tried my best , but fails . Please help me to get rid out from this

- 5 years ago

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exactly. was thinking the same way.

Original question is from NCERT Exemplar.

Chapter 11 . QNo 13.

- 5 years ago

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