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Most Difficult Redox Equation

this is one of the hardest redox equations.

the problem is:

CuSCN + KIO3 + HCl === CuSO4 + KCl + HCN + ICI + H2O

Acid Or Base Does Not Matter.

Please Post Solutions...

Note by Anika .
2 years, 1 month ago

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Here you go:

\(\underline{4}CuSCN+\underline{7}KIO_3+\underline{14}HCl=\underline{4}CuSO_4+\underline{7}KCl+\underline{4}HCN+\underline{7}ICl+\underline{5}H_2O\) John Muradeli · 2 years, 1 month ago

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By redox equations do you mean like \(2H_2+O_2=2H_2O\)? Ok so I need to balance

\(\underline{\hspace{2mm}} CuSCN+\underline{\hspace{2mm}}KIO_3+\underline{\hspace{2mm}}HCl=\underline{\hspace{2mm}}CuSO_4+\underline{\hspace{2mm}}KCl+\underline{\hspace{2mm}}HCN+\underline{\hspace{2mm}}ICl+\underline{\hspace{2mm}}H_2O\)

Sounds interesting. I shall give it a try.

P.S. here's the latex for the equation:

\underline{\hspace{2mm}}CuSCN+\underline{\hspace{2mm}}KIO3+\underline{\hspace{2mm}}HCl=\underline{\hspace{2mm}}CuSO4+\underline{\hspace{2mm}}KCl+\underline{\hspace{2mm}}HCN+\underline{\hspace{2mm}}ICl+\underline{\hspace{2mm}}H_2O\ John Muradeli · 2 years, 1 month ago

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Are all they in aqeuous state?? Shivam Gupta · 1 year, 4 months ago

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any eqn in chemistry can be balanced by assuming coefficients as 1,a,b,c,d.....simply equate no of each atoms on both sides.

CuSCN + aKIO3 + bHCl === cCuSO4 + dKCl + eHCN + fICI + gH2O

u may get fractions but multiply by lcm of denominators.

But this doesnt mean i can do any Q from chem.... i am very bad at it just like oil with water(does not go together) Incredible Mind · 1 year, 8 months ago

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