this concept in the picture was used to solve the problem, but I don't know about this concept and I couldn't search for it in Google . it apparently isn't matrix

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TopNewestits 7 choose 4 and 9 choose 2, counting... – Kee Wei Lee · 4 years, 1 month ago

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If there are 6 ones, then the 4 zeroes can go in 7 possible positions, and there are (74) ways to do this. If there are 8 ones, then the remaining 2 zeros can go in 9 possible positions, giving (92) ways. If there are 10 ones, there are no zeros to be placed. Thus, the answer is

I don't understand this part "then the 4 zeroes can go in 7 possible positions, and there are (74) ways to do this" sorry for disturbing – Abdo Saeed · 4 years, 1 month ago

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1111_1 _. Here there are six 1s' and seven _ spaces. Since we cannot place two consecutive 0s' together we have to place them in the _ spaces. So we have 7 places to put 4 zeroes, (7 4) – Kee Wei Lee · 4 years, 1 month agoLog in to reply

– Abdo Saeed · 4 years, 1 month ago

OK thank you I just didn't know that way of writing chooseLog in to reply

@Abdo It's best for you to make such comments in the solution discussion itself.

Note that the link is customized to you, and no one else will be able to view it. You need to use the "Share this problem" link instead. I've removed the link you provided. – Calvin Lin Staff · 4 years, 1 month ago

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