Although I'm in Class 12,but I couldn't stop myself from taking a glance at this year's JEE Math's questions. I found this question to be very intriguing and so I thought of sharing it with my Brilliant friends.

For \(a \in R\) (set of real numbers) , \(a \neq -1\), \[lim_{n \to \infty}\frac{1^a+2^a+ \ldots +n^a}{(n+1)^{a-1}[(na+1)+(na+2)+\ldots+(na+n)]}= \frac{1}{60}\] Then \(a=?\)

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## Comments

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TopNewestThe answers are

7and \(\frac{-17}{2}\). The trick here was to first express thelimitin form of summation(\(\Sigma\)) and then change summation in definite integration(\(\int_0^1\)).Log in to reply

8888

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Log questions based on first significant digit

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Please solve your question

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Write a comment or ask a question...can you give me the solution

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i just did trail and error....

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Determine K so that 2÷3 ,K and 5÷3×k are three consecutive term of an AP

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Answer is 7 or -17/2 ....i guess...

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a=7 is only accepted

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I got two answers....a=7 and a= -7/5, but the answer key gives only one. I got a quadratic equation at the end.

Anybody else got the same result?

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You got it?

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how?

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a=7

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were there any options given??

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Yes, its a multiple correct answers question.

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how to improve maths skill

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what's JEE?

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It's the most competitive Engineering Entrance Exam in India.It questions on Physics,Chemistry and Mathematics......

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joint entrance examinations

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they really gave such easy questions this year?JEE has been diluted.

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Good thing you didn't see the Physics section...

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I took a look,and I see no reason of deviating from my stand.I didn't see anything much innovative,except for a hydrostatics problem in paper 1,and a couple of matching type questions in paper 2.Even those were not really tough,just needed keeping your head cool.Trust me,JEE has seen much better days.

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the chemistry questions were tough, but the maths and the physics questions were found very easy to me.

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