Waste less time on Facebook — follow Brilliant.
×

need help

Note by Ponty Pawha
4 years ago

No vote yet
0 votes

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

Please help me in this simple problem We have a sequence of 100 positive integers. The average of the first and second numbers is 1. The average of the second and third numbers is 2. The average of the third and fourth numbers is 3. This pattern continues, and the average of the 99th and 100th number is 99. What is the 100th number?

Ponty Pawha - 4 years ago

Log in to reply

I've seen this somewhere I think, and in the variant form the numbers were not necessarily integers but all distinct.

In this sequence would it be possible to have 1,1,3,3,5,5,7,7...? If so, then 99 would be your answer. I wish I remember where this is from...

Spock Weakhypercharge - 3 years, 7 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...