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Note by Ponty Pawha
3 years, 5 months ago

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Please help me in this simple problem We have a sequence of 100 positive integers. The average of the first and second numbers is 1. The average of the second and third numbers is 2. The average of the third and fourth numbers is 3. This pattern continues, and the average of the 99th and 100th number is 99. What is the 100th number? Ponty Pawha · 3 years, 5 months ago

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@Ponty Pawha I've seen this somewhere I think, and in the variant form the numbers were not necessarily integers but all distinct.

In this sequence would it be possible to have 1,1,3,3,5,5,7,7...? If so, then 99 would be your answer. I wish I remember where this is from... Spock Weakhypercharge · 3 years ago

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