A projectile proton with a speed of 200 m/s collides elastically with a target proton initially at rest. The two protons then move along perpendicular paths, with the projectile path deviating by 60∘ from its original direction. After the collision, what is the approximate speed of the target proton?

Please help me.. I have no idea at all.. What i think is the speed become 200 *cos60.. But, it says that the correct answer is 170 which is approximate to 200*sin60... Please explain me how to solve the problem step by step

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