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natural number from 1 to 2013 are written in a series. Can we get its sum zero by placing + or - sign between them? If yes then by how many + and how many -? If no why? Justify your answer with proper logic.

Note by Parv Parkhiya 4 years, 7 months ago

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*italics*

_italics_

**bold**

__bold__

- bulleted- list

1. numbered2. list

paragraph 1paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)

> This is a quote

This is a quote

# I indented these lines # 4 spaces, and now they show # up as a code block. print "hello world"

2 \times 3

2^{34}

a_{i-1}

\frac{2}{3}

\sqrt{2}

\sum_{i=1}^3

\sin \theta

\boxed{123}

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No. Consider parity 2.

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Sorry, I don't get it...."consider parity 2." ???????????

+- 1 +- 2 +- 3 +- ... +- 2013 = 0

LHS mod 2 = 1, RHS mod 2 = 0, contradiction

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Easy Math Editor

`*italics*`

or`_italics_`

italics`**bold**`

or`__bold__`

boldNote: you must add a full line of space before and after lists for them to show up correctlyparagraph 1

paragraph 2

`[example link](https://brilliant.org)`

`> This is a quote`

Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.`2 \times 3`

`2^{34}`

`a_{i-1}`

`\frac{2}{3}`

`\sqrt{2}`

`\sum_{i=1}^3`

`\sin \theta`

`\boxed{123}`

## Comments

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TopNewestNo. Consider parity 2.

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Sorry, I don't get it...."consider parity 2." ???????????

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+- 1 +- 2 +- 3 +- ... +- 2013 = 0

LHS mod 2 = 1, RHS mod 2 = 0, contradiction

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