Waste less time on Facebook — follow Brilliant.
×

Need help In Rocket Physics (1)

Image

Image

Fuel is ejected from a rocket of mass \({ M }_{ 0 }\) at a velocity \(u\) \(m/s\) relative to Rocket. Fuel is ejecting at constant rate of \(\mu \quad Kg/s\). Initial Velocity rocket starts from rest from the surface of earth

( Neglect air and other resistance force in both Cases)

Q1). Assume gravity is constant , Find acceleration, velocity and Thrust as a function of time.

Q2). Assume gravity changes with height \(h\) from earth surface as \(g\left( h \right) =\frac { g }{ { \left( 1+\frac { h }{ { R }_{ e } } \right) }^{ 2 } } \), Find acceleration, Velocity and Thrust as a function of time.

Note by Rishabh Deep Singh
1 year, 7 months ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

Use impulse momentum theoerem in both cases Consider any arbitrary moment in time t and distance y from surface of earth Let us consider that rocket as my system with mass at that point in spacetime as m In time dt let dm mass be ejected absolute velocity of dm is u-v where u is the relative velocity and v is the absolute velocity of rocket at that moment Impulse due to weight is mgdt which is the change in momentum of the system that is rocket After this we form a differentia equation which is dificult to solve in case 2 I am not able to solve the equation In case 1 V= uln(m■\m) -g\p(m■-m) Where m■ is initia mass p is dm\dt

Akash Yadav - 5 months, 1 week ago

Log in to reply

Is acceleration \(\frac{\mu u}{M_{0} -\mu t}\) ?

Harsh Shrivastava - 1 year, 7 months ago

Log in to reply

How do you find it ?? I don't know the answer.

Rishabh Deep Singh - 1 year, 7 months ago

Log in to reply

Use conservation of momentum and a=dv/dt.

Harsh Shrivastava - 1 year, 7 months ago

Log in to reply

@Harsh Shrivastava You are totally wrong.

We can't apply conservation of momentum as there is gravity and also mass is changing with Time.

Rishabh Deep Singh - 1 year, 7 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...