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If \(h\) be the height due to the velocity \(v\) at the earth's surface, supposing the acceleration due to gravity to be constant, and \(H\) the corresponding height when the variation of gravity is taken into account, prove \(\frac{1}{h} - \frac{1}{H} = \frac{1}{R}\), where \(R\) is the radius of the earth.

Note by Swapnil Das
11 months, 1 week ago

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Rohit Ner · 11 months, 1 week ago

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