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New types of congruences?

Well these congruences are pretty basic and trivial but I didn't find anything about them in books or on net.

It is interesting to note the following congruences.

\[1) \phi(a)^n \equiv \phi(a) \mod a\] Here , \(a\) is arbitary prime number and \(n\) is any odd number.


\[2) \phi(a)^{n'} \equiv 1\mod a\] Here \(a\) is any arbitary prime and \(n'\) is an arbitary even number.


Note by Chinmay Sangawadekar
6 months, 3 weeks ago

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Comment deleted 6 months ago

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@Chinmay Sangawadekar Yes, they are true... it amounts to \((-1)^n=-1\) for odd \(n\) and \((-1)^n=1\) for even \(n\). Otto Bretscher · 6 months, 3 weeks ago

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@Otto Bretscher Not actually , as \(\phi (a)\) can't be less than one right ? @Otto Bretscher Chinmay Sangawadekar · 6 months, 3 weeks ago

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@Chinmay Sangawadekar \(\phi(a)\equiv -1\pmod{a}\) Otto Bretscher · 6 months, 3 weeks ago

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@Otto Bretscher Ah , how could I miss that !! anyway can you construct any problem which could be solved by these congruences ? I had one problem in my mind , simplifying the towers of integers becomes a lot easy by these congruences...@Otto Bretscher Chinmay Sangawadekar · 6 months, 3 weeks ago

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@Chinmay Sangawadekar You know, I'm a guy with a short attention span. I soon get tired of a certain "type" of problem (like those congruences) and move on to something else. I'm sure you can come up with great examples. Otto Bretscher · 6 months, 3 weeks ago

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@Chinmay Sangawadekar who knows ;) Otto Bretscher · 6 months, 3 weeks ago

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@Otto Bretscher Experienced Mathematician like you ;) @Otto Bretscher Chinmay Sangawadekar · 6 months, 3 weeks ago

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