# Nice problem!

Find all integer solution to $\frac{2}{a^{2}}+\frac{3}{b^{2}}+\frac{4}{c^{2}}=1$. Just give me a correct hint or the approach with which I must start it.Please dont give me the solution.

Note by Kishan K
7 years, 2 months ago

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## Comments

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I have posted the name of the website.Many of you would be knowing it, or everyone would be.Don't go for this book it has very few questions, go for Problem Solving Strategies...Best ever book......Try to solve first few problems of it,I am not telling to solve all but few, and try to solve as many as u can....

- 7 years, 1 month ago

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is it possible with just one equation?

- 7 years, 2 months ago

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Listen Kevin. You have got skill, talent and opportunity in front of you. Don't waste it trying to pursue some engineering degree from IIT. Instead, develop your skill and try to advance in a science stream of your choice. This is just my opinion out of my personal experience. No hard feelings against any engineering degree, engineers or any IIT.

- 7 years, 2 months ago

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subhrodiptob@yahoo.com! i am amazed my your mathematics excellence at age of only 13!!!

- 7 years, 2 months ago

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Go to http://www.amtionline.com/

- 7 years, 2 months ago

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This book is not very good it is not for exam of higher level than your local exams conducted my private companies.Questions on brilliant are far far better than this.So don't bother about it anymore.Yes, If u really want to excel in mathematics get Problem Solving Strategies.Really, you will enjoy it.

- 7 years, 2 months ago

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cool prob which book u get this from?- mooremichael493@gmail

- 7 years, 2 months ago

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Kevin, can i get your book in pdf or in word to 'playing' with your exc? my email is umaraburrohman.94@gmail.com

- 7 years, 2 months ago

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There's a general trick here: attempt to bound one of the terms.

Let m = min(a, b, c), then $a \ge m \implies \frac 1 {a^2} \le \frac 1 {m^2}$. Then:

$1 = \frac 2 {a^2} + \frac 3 {b^2} + \frac 4 {c^2} \le 4\left( \frac 1 {a^2} + \frac 1 {b^2} + \frac 1 {c^2}\right) \le \frac {12}{m^2}$

So $m^2 \le 12$ and m = 2, 3. Consider each of a=2,3; b=2, 3 and c=3.

- 7 years, 2 months ago

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What's the source of this problem?

- 7 years, 2 months ago

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My book.

- 7 years, 2 months ago

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what's the name of the book?

- 7 years, 2 months ago

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Which one is it? Does it contain more problems like this?

- 7 years, 2 months ago

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Give me ur email, I will send u all information of it.

- 7 years, 2 months ago

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pls send me too.....my mail is kislay4raj@gmail.com

- 7 years, 1 month ago

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here potsunsi@yahoo.com i really interested..

- 7 years, 2 months ago

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chaukhanh1603@yahoo.com.vn

- 7 years, 2 months ago

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Kevin, I want too, my email: leonardochandra@hotmail.com. Thanks

- 7 years, 2 months ago

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Yes many.

- 7 years, 2 months ago

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i am interested also.... heres my email mharfemicaroz@gmail.com

please send to me.. i have very poor math skills:(

- 7 years, 2 months ago

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may I have one? serlyayus@gmail.com

- 7 years, 2 months ago

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me too ............ anshul99agr@gmail.com

- 7 years, 2 months ago

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give it to mee too

advitiyabrijesh@gmail.com

- 7 years, 2 months ago

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