NMTC 2015 is over! How well did you perform?

Hey guys after a long wait finally NMTC was conducted on 22nd August in all parts of the country.SO how well did you fare? What is expected score of yours and the cut-off you expect. .Kindly share your views about the Question paper or the interesting questions.Don't forget to share your expected marks.

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Hi! Mohit , the most interesting question and easy question according to me was -

Find the number of integeral solutions of the following inequality,

$(n^{2}-2)(n^{2}-20)<0$

Which one was yours?

Akshay Yadav - 4 years, 11 months ago

For me the easiest question was q7. A nom divided by 899 gives a remainder 63. The remainder when this no. Is divided by 29 is

Satyajit Ghosh - 4 years, 11 months ago

Ha Ha ..... it was the $easiest$ question.

Akshat Sharda - 4 years, 11 months ago

The answer was 6 na?

Kushagra Sahni - 4 years, 11 months ago

No the ans. Was 6 .I am pretty sure about it.

Mohit Gupta - 4 years, 11 months ago

@Mohit Gupta – Yeah I am sorry the answer was 6

Kushagra Sahni - 4 years, 11 months ago

I am expecting 27 or 28. What about you?

Kushagra Sahni - 4 years, 11 months ago

can anyone tell what was the answer of the log question...... is it 890 or 841+ $\sqrt{7}$ on AMTI site it is 890 Go here and on Allen site it is 841+ $\sqrt{7}$ Go here TO all csquarians,Ad sir first gave the answer as 890 then we have consulted to sir then he gave answer as 841+ $\sqrt{7}$ still Its so confusing can anyone tell me the answer with well surity...

sakshi rathore - 4 years, 11 months ago

Answer is 841+root7 you can confirm it.I AM 120 PERCENT SURE.....

Mohit Gupta - 4 years, 11 months ago

Did you get selected?

Kushagra Sahni - 4 years, 10 months ago

@Kushagra Sahni – Ya bro.............even i got selected for LEVEL 2

Mohit Gupta - 4 years, 9 months ago

Yeah the answer is surely 841+ root 7

Kushagra Sahni - 4 years, 11 months ago

Answer is $\boxed{841+\sqrt{7}}$

Akshat Sharda - 4 years, 11 months ago

I got selected for stage 2.

Kushagra Sahni - 4 years, 11 months ago

is the result declared

sakshi rathore - 4 years, 11 months ago

Yeah I gave it from FIITJEE South Delhi Center and they declared the result on their site for only FIITJEE students. From the result it seems that the cut off was 15. It may be lower elsewhere because fiitjee's cut off is always higher even last time in NMTC it was higher than what it should have been.

Kushagra Sahni - 4 years, 11 months ago

@Kushagra Sahni – Great!!!!!! I Don't have question paper so can't estimate my EXACT marks......but you have done so well .Do you get marks more than 25 as you said?also what your rank among FIIT JEE STUDENTS.?

Harshi Singh - 4 years, 11 months ago

Hey kushagra great. ...........CONGRATS..... wonderful job done. ...... i'm still waiting for my results. ......again CONGRATS....

Mohit Gupta - 4 years, 11 months ago

Thnx mate. I wish you best of luck for the results.

Kushagra Sahni - 4 years, 11 months ago

Hey did anyone notice a controversial question. The question which has a cube root and a sixth root.This question has two answers 1 & -1

Mohit Gupta - 4 years, 11 months ago

No answer was 1. Because -1 would be an extraneous root.

Kushagra Sahni - 4 years, 11 months ago

Hey come on man....cube root of -1 has three values...two lie in complex plane and one lie in real plane i.e. -1

Mohit Gupta - 4 years, 11 months ago

@Mohit Gupta – Do you know that square root of any number is mod x? If you don't then please keep this in your mind as this concept will help you in many exams. If I go 300 days back I had the same doubt as yours but my teacher told me that square root has to be non- negative always.

Kushagra Sahni - 4 years, 11 months ago

@Kushagra Sahni – I am saying about cube root not square root cube root of a negative number has a negative ans. Also........

Mohit Gupta - 4 years, 11 months ago

@Mohit Gupta – Hey when you converted 6th root to 3rd root that's where the whole problem lies. And that is taking square root and not cube root and if you took the root as root2-1 then you will get 1 which is correct as root2-1 is positive. However, if you take 1-root2 which is negative then I am afraid you will get -1 which is wrong.

Kushagra Sahni - 4 years, 11 months ago

@Kushagra Sahni – Ya...... oh what a dammm sillllllllly mistake i have done.unbeleivable?? Neverthless 1+1/4 marks are gone.

Mohit Gupta - 4 years, 11 months ago

@Mohit Gupta – Don't worry you can do better next time, we learn from mistakes and even I did silly mistakes.

Kushagra Sahni - 4 years, 11 months ago

Which question are you saying?

Priyanshu Mishra - 4 years, 10 months ago

Hello Mohit!

The question 14 was very interesting.

I solved like this:

I set ${ 2 }^{ x }=a$ and ${ 3 }^{ x }=b$ and then simplified to get

$\huge\ \frac { { a }^{ 3 }+{ b }^{ 3 } }{ { a }^{ 2 }b+a{ b }^{ 2 } } =\frac { 7 }{ 6 }$

i.e, $\large\ \frac { { a }^{ 2 }-ab+{ b }^{ 2 } }{ a{ b } } =\frac { 7 }{ 6 }$

i.e, $6{ a }^{ 2 }-13ab+6{ b }^{ 2 }=0$

i.e, $(2a-3b)(3a-2b)=0$

which on solving yields $x=1$ and $x=-1$ .

How you solved that? Also how much you expected?

Priyanshu Mishra - 4 years, 10 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$