Hey guys after a long wait finally NMTC was conducted on 22nd August in all parts of the country.SO how well did you fare? What is expected score of yours and the cut-off you expect. .Kindly share your views about the Question paper or the interesting questions.Don't forget to share your expected marks.

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TopNewestHi! Mohit , the most interesting question and easy question according to me was -

Find the number of integeral solutions of the following inequality,

\((n^{2}-2)(n^{2}-20)<0 \)

Which one was yours? – Akshay Yadav · 1 year, 2 months ago

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– Satyajit Ghosh · 1 year, 2 months ago

For me the easiest question was q7. A nom divided by 899 gives a remainder 63. The remainder when this no. Is divided by 29 isLog in to reply

– Kushagra Sahni · 1 year, 2 months ago

The answer was 6 na?Log in to reply

– Mohit Gupta · 1 year, 2 months ago

No the ans. Was 6 .I am pretty sure about it.Log in to reply

– Kushagra Sahni · 1 year, 2 months ago

Yeah I am sorry the answer was 6Log in to reply

– Akshat Sharda · 1 year, 2 months ago

Ha Ha ..... it was the \(easiest\) question.Log in to reply

I got selected for stage 2. – Kushagra Sahni · 1 year, 1 month ago

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– Sakshi Rathore · 1 year, 1 month ago

is the result declaredLog in to reply

– Kushagra Sahni · 1 year, 1 month ago

Yeah I gave it from FIITJEE South Delhi Center and they declared the result on their site for only FIITJEE students. From the result it seems that the cut off was 15. It may be lower elsewhere because fiitjee's cut off is always higher even last time in NMTC it was higher than what it should have been.Log in to reply

– Harshi Singh · 1 year, 1 month ago

Great!!!!!! I Don't have question paper so can't estimate my EXACT marks......but you have done so well .Do you get marks more than 25 as you said?also what your rank among FIIT JEE STUDENTS.?Log in to reply

– Mohit Gupta · 1 year, 1 month ago

Hey kushagra great. ...........CONGRATS..... wonderful job done. ...... i'm still waiting for my results. ......again CONGRATS....Log in to reply

– Kushagra Sahni · 1 year, 1 month ago

Thnx mate. I wish you best of luck for the results.Log in to reply

can anyone tell what was the answer of the log question...... is it 890 or 841+\(\sqrt{7}\) on AMTI site it is 890 Go here and on Allen site it is 841+\(\sqrt{7}\) Go here TO all csquarians,Ad sir first gave the answer as 890 then we have consulted to sir then he gave answer as 841+\(\sqrt{7}\) still Its so confusing can anyone tell me the answer with well surity... – Sakshi Rathore · 1 year, 1 month ago

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Answeris \(\boxed{841+\sqrt{7}}\) – Akshat Sharda · 1 year, 1 month agoLog in to reply

– Kushagra Sahni · 1 year, 1 month ago

Yeah the answer is surely 841+ root 7Log in to reply

– Mohit Gupta · 1 year, 1 month ago

Answer is 841+root7 you can confirm it.I AM 120 PERCENT SURE.....Log in to reply

– Kushagra Sahni · 1 year ago

Did you get selected?Log in to reply

– Mohit Gupta · 1 year ago

Ya bro.............even i got selected for LEVEL 2Log in to reply

I am expecting 27 or 28. What about you? – Kushagra Sahni · 1 year, 2 months ago

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Hello Mohit!

The question 14 was very interesting.

I solved like this:

I set \({ 2 }^{ x }=a\) and \({ 3 }^{ x }=b\) and then simplified to get

\(\huge\ \frac { { a }^{ 3 }+{ b }^{ 3 } }{ { a }^{ 2 }b+a{ b }^{ 2 } } =\frac { 7 }{ 6 }\)

i.e, \(\large\ \frac { { a }^{ 2 }-ab+{ b }^{ 2 } }{ a{ b } } =\frac { 7 }{ 6 }\)

i.e, \(6{ a }^{ 2 }-13ab+6{ b }^{ 2 }=0\)

i.e, \((2a-3b)(3a-2b)=0\)

which on solving yields \(x=1\) and \(x=-1\).

How you solved that? Also how much you expected? – Priyanshu Mishra · 1 year ago

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Hey did anyone notice a controversial question. The question which has a cube root and a sixth root.This question has two answers 1 & -1 – Mohit Gupta · 1 year, 2 months ago

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– Kushagra Sahni · 1 year, 2 months ago

No answer was 1. Because -1 would be an extraneous root.Log in to reply

– Mohit Gupta · 1 year, 2 months ago

Hey come on man....cube root of -1 has three values...two lie in complex plane and one lie in real plane i.e. -1Log in to reply

– Kushagra Sahni · 1 year, 2 months ago

Do you know that square root of any number is mod x? If you don't then please keep this in your mind as this concept will help you in many exams. If I go 300 days back I had the same doubt as yours but my teacher told me that square root has to be non- negative always.Log in to reply

– Mohit Gupta · 1 year, 2 months ago

I am saying about cube root not square root cube root of a negative number has a negative ans. Also........Log in to reply

– Kushagra Sahni · 1 year, 2 months ago

Hey when you converted 6th root to 3rd root that's where the whole problem lies. And that is taking square root and not cube root and if you took the root as root2-1 then you will get 1 which is correct as root2-1 is positive. However, if you take 1-root2 which is negative then I am afraid you will get -1 which is wrong.Log in to reply

– Mohit Gupta · 1 year, 2 months ago

Ya...... oh what a dammm sillllllllly mistake i have done.unbeleivable?? Neverthless 1+1/4 marks are gone.Log in to reply

– Kushagra Sahni · 1 year, 2 months ago

Don't worry you can do better next time, we learn from mistakes and even I did silly mistakes.Log in to reply

– Priyanshu Mishra · 1 year ago

Which question are you saying?Log in to reply