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No Olympiad Problems? [Resolved]

What happened to the new problems for this week?

Note by Vishwa Iyer
4 years, 5 months ago

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Oh man..I even woke up early to do the new problems today.. Thaddeus Abiy · 4 years, 5 months ago

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@Thaddeus Abiy same over here.. sad. :( Ahmed Abid Abbash · 4 years, 5 months ago

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Hi everyone,

This was a glitch and has been corrected. You can see new Olympiad problems now. We are very sorry for the mistake.

Happy problem solving! Silas Hundt Staff · 4 years, 5 months ago

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@Silas Hundt why are some of them recycled though??Ive seen them before..or is it just me Thaddeus Abiy · 4 years, 5 months ago

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@Thaddeus Abiy Yes, i too saw at least 2 repeated questions. Rohan Rao · 4 years, 5 months ago

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@Rohan Rao They didn't even bother to change the number of people it's been solved by..I don't like remembering problems I like solving them..Please brilliant,If you are going to recycle problems,At least change the numbers Thaddeus Abiy · 4 years, 5 months ago

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@Thaddeus Abiy I think they must have been working on the new problem bank this week and thus didn't have time to create/present new problems. David Altizio · 4 years, 5 months ago

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@Thaddeus Abiy Yeah... Tan Li Xuan · 4 years, 5 months ago

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They are probably behind, or saving something because of the revamp of curriculum mathematics that is being done. So I bet they are working very hard this week! Lets find problems other places. If you have any good problems you would like to share, please post them as a reply so that everyone can have problems to do while waiting.

Here, An auditorium has a rectangular array of chairs. There are exactly 14 boys seated in each row and exactly 10 girls seated in each column. If exactly 3 chairs are empty, find the maximum number of chairs in the auditorium. Brock West · 4 years, 5 months ago

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@Brock West If you wanna keep this going, then here's a GREAT problem from the 1983 ARML competition:

In an isosceles triangle, the altitudes intersect on the inscribed circle. Compute the cosine of the vertex angle. David Altizio · 4 years, 5 months ago

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@David Altizio Should I post a solution for this one? Its a fairly simple exercise in trigonometry, but there will be people still trying to solve this one.

I arrived at the answer 1/9 (assuming you are taking the cosine of the 'unique' angle) Gabriel Wong · 4 years, 5 months ago

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@Gabriel Wong It says 'vertex angle', so yea your answer is correct.

Don't post the solution though; while its a relatively simple problem I still like it for having such an interesting condition. David Altizio · 4 years, 5 months ago

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@David Altizio Thanks for posting! :) Ahaan Rungta · 4 years, 5 months ago

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@Brock West try this: 1=6 2=12 3=18 4=24 5=30 6=?? Jon-jon Castro · 4 years, 5 months ago

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@Jon-jon Castro 1,because 1=6,so 6=1 :) Tan Li Xuan · 4 years, 5 months ago

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@Tan Li Xuan 6 = 6, obviously Zi Song Yeoh · 4 years, 5 months ago

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@Jon-jon Castro Yes 6=6 obviously but if the equal to mean's multiply by 6 its 36 Thaddeus Abiy · 4 years, 5 months ago

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@Jon-jon Castro 1 is correct Jon-jon Castro · 4 years, 5 months ago

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@Jon-jon Castro 1 = 6 is illogical Zi Song Yeoh · 4 years, 5 months ago

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@Zi Song Yeoh because 1=6,so 6=1 Tan Li Xuan · 4 years, 5 months ago

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@Brock West Under the assumption that boys and girls cannot share a chair, let number of rows and columns be r and c. (r >= 14; c >= 10)

Then rc = 3+14r+10c

rc-14r-10c-3 = 0

rc - 14r - 10c +140 - 143 = 0

(r-10)(c-14) = 143

Now, the possibilities for (r,c) are (1,143), (11,13), (13,11) and (143,1). Checking all 4, the number of chairs in each is (11)(157), (21)(27), (23,25), (153,15).

Clearly (23)(25) > (21)(27) and (11)(157)<(153)(15). (if a>c>d>b>0 and a+b = c+d, ab < cd) Also, (153)(15) > (23)(25) obviously.

The maximum number of chairs is thus (153)(15) = 2295 (with 2292 chairs filled up) Gabriel Wong · 4 years, 5 months ago

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@Gabriel Wong why ? defining X = r-10, Y = c-14, then that means X = 1,Y = 143 -> r = 11, c 157 -> rc = 1727 X = 11, Y = 13 -> r = 21, c = 27 -> rc = 567 X = 13, Y = 11 -> r = 23, c = 25 -> rc = 575 X = 143, Y = 1 -> r = 153, Y = 15 -> rc = 2295 (This is the max number of chairs) Raymond Christopher Sitorus · 4 years, 5 months ago

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@Raymond Christopher Sitorus I think the answer would be rc and not rc-3 though, since the three chairs that are empty are still chairs in the array. David Altizio · 4 years, 5 months ago

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@David Altizio thx David for correcting Raymond Christopher Sitorus · 4 years, 5 months ago

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@Gabriel Wong Why doesn't, say, r=21 and c=27 work? David Altizio · 4 years, 5 months ago

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@David Altizio was wrong initially, edited Gabriel Wong · 4 years, 5 months ago

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I hate it.. I hope they can fix it as soon as possible.. Neil Tinaytina · 4 years, 5 months ago

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There will be a lot to look forward to; new challenges and a huge database will be up tomorrow or Tuesday. Peter T. posted this earlier. I can't find a link at the moment, sorry! Ahaan Rungta · 4 years, 5 months ago

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I got the same problem... Hope they fixed it soon. André Macedo · 4 years, 5 months ago

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problems are back yepiii!!!!!!!!!!!!!!!!!!!!! Tejas Kasetty · 4 years, 5 months ago

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They're up now. Kenneth Chan · 4 years, 5 months ago

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Why arent there any qns today? I thought they post qns here every Monday?!?! YuJiahuan LuvRafflesfriends · 4 years, 5 months ago

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I hope they will bring new things.I will wait with patience Shaheed Vh · 4 years, 5 months ago

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:( Advitiya Brijesh · 4 years, 5 months ago

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But atleast they could send the weekly problems of one of the Olympiad sections. I'll get bored.... Garvil Singhal · 4 years, 5 months ago

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Hopefully it's just because they're upgrading the techniques trainer. Clifford Wilmot · 4 years, 5 months ago

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@Clifford Wilmot Hopefully Vishwa Iyer · 4 years, 5 months ago

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i cant see my trignometry & calculus problems since 2 weeks... Nikhil Tr · 4 years, 5 months ago

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@Nikhil Tr can you?? Nikhil Tr · 4 years, 5 months ago

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