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# Note 1

• Help Needed

Factorize $$(1+y)^{2}-2x^{2}(1+y^{2})+x^{4}(1-y)^{2}$$.

Note by Jason Snow
1 year ago

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It can be written as: $((1+y)^2-\color{forestgreen}{2x^{2}(1-y^{2})}+x^{4}(1-y)^{2})+\color{forestgreen}{2x^{2}(1-y^{2})}-2x^2(1+y^2)$ $=((1+y)-x^2(1-y))^2-4x^2y^2$ $=((1+y)-x^2(1-y)+2xy)((1+y)-x^2(1-y)-2xy)$ $\small{\color{blue}{Using\space p^2-q^2=(p+q)(p-q)}}$ · 1 year ago

THANK YOU :D · 1 year ago

Though I managed to factorize the given expression but factored terms are altogether different from that of Rishabh Cool's answer. The given expression can be written as :- $(1+y)^{2}-2x^{2}(1+y^{2})+x^{4}(1-y)^{2}\,=\,( \color{blue}{ 1+y^{2}}+2y)-2x^{2}(\color{blue}{1+y^{2}})+x^{4}( \color{blue}{1+y^{2}}-2y)$ $\implies (\color{blue}{1+y^{2}})+2y-2x^{2}(\color{blue}{1+y^{2}})+x^{4}(\color{blue}{1+y^{2}})-2x^4y$ $\implies (\color{blue}{1+y^{2}})(1-2x^{2}+x^{4})+2y(1-x^{4})$ $\implies (\color{blue}{1+y^{2}})(\color{red}{1-x^{2})^{2}}+2y(\color{red}{1-x^{2}})(1+x^{2})$ $\implies (\color{red}{1-x^{2}}) \left( (\color{blue}{1+y^{2}})(\color{red}{1-x^{2}})+2y(1+x^{2}) \right)$ · 10 months ago