Pretty much in the title but.. well im trying to find a formula for the nth time derivative of sin(x) (where the x is a position just so you know its not me wanting to find the nth derivative of sin(t) hehe).

im wondering if there is another route to finding a formula other than taking like hundreds of product rule derivatives (or using thhe leibniz formula for product rules which isn't getting me very far since its like an infinite substitution thing (if u want me to explain what i mean ask xD)) and looking for tough to spot pattern, or if its even really possible to find a formula

## Comments

Sort by:

TopNewestLet y = sin(x) Differentiating wrt x, y'= cos(x) = sin(π/2 +x) Similarly yn or nth derivative of sinx wrt x is sin(nπ/2 + x) – Shashank Rustagi · 1 year, 11 months ago

Log in to reply

I don't think I understand your question but do you mean this?

\[\begin{array}{l} f(x) = {\sin ^n}x\\ f'(x) = n{\sin ^{n - 1}}x\cos x \end{array}\] – Samuel Hatin · 3 years, 8 months ago

Log in to reply

– Jord W · 3 years, 8 months ago

no, i mean if you take the derivative with respect to t of sin(x) n times, what would u get so for example, if you did it once, you'd get cos(x) dx/dt.. if you did another derivative, you'd get cos(x)d2x/dt2-sin(x) dx/dt... etc, im wondering if theres some way to figure out a formula for thatLog in to reply

– Arshad Khalid · 3 years, 7 months ago

nth derivative of logx(sinx) by leibiniz theorem? plz guide meLog in to reply

– Arshad Khalid · 3 years, 7 months ago

nth derivatine of logx(sinx) by leibiniz theorem? plzzzzzzzzzz plzzzzzzzzzzzzzzz guide usLog in to reply

yeah! i 'm looking for leibniz theorem – Arshad Khalid · 3 years, 7 months ago

Log in to reply

nth derivatine of logx(sinx) by leibiniz theorem – Arshad Khalid · 3 years, 7 months ago

Log in to reply

– Arshad Khalid · 3 years, 7 months ago

someone hereLog in to reply