A number can be expressed as a sum of two or more odd integers/numbers. For example:

\(35 = 5 + 5 + 5 + 5 + 5 + 5 + 5\)

\(48 = 35 + 3 + 1 + 1 + 5 + 3\)

\(10 = 1 + 1 + 1 + 7\)

Can you think of 7 odd numbers/integers that would result of a sum of 20???

NOTE: The numbers can't be a decimal, fractions, radicals, etc. It must be a whole number. You may use any method you'll like as long as you prove that there are 7 odd numbers that would have a sum of 20.

GOOD LUCK!

P.S. I don't know the answer by the way. I just curious if is possible. Sorry.

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TopNewestHow much time have you spent on it? Have you tried to prove that it's impossible?

I'm going to try to steer you into the right direction.

Add two odd numbers. Is the resulting number odd or even?

Add three odd numbers. Is the resulting number odd or even?

Add an even number of odd numbers. Is the resulting number odd or even?

Add an odd number of odd numbers. Is the resulting number even or odd?

Note that \(20\) is an even number and \(7\) is an odd number.

Can you take it from here? – Mursalin Habib · 2 years, 5 months ago

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– Jay Cyril Mijares · 2 years, 5 months ago

okay . . . let's see.Log in to reply