Consider an

rectangular glassboard $ABCD$ , with surfaces $AB$, $BC$, $CD$ areperfectly silvered. An smalllaser lightis set in the corner $A$ (negligible dimensions) . Now just for fun , this laser light is set in such a way so that light ray first travel from A making an angle $\theta$ with side $AD$ and thentotally reflectedby surfaces $DC$ , then $CB$ , then $BA$ and finallyrefractedout from surface $AD$. If during this event , anquadrilateraland antriangleare traced out as shown & their point of intersection is $P$, Such thatAreaof triangle( $APT$ ) is equal to that of quadrilateral( $PQRS$ ).

**Given that** :

$AB=CD=2(BC)=2(AD)$

$\text{Laws of reflection holds perfectly}$.

Then find that particular angle $\theta$ in degrees or just simply prove that $\tan { \theta } =\cfrac { a-\sqrt { b } }{ c }$ and find $a+b+c$ , for which such event is possible.

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## Comments

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TopNewestI get Tan(theta)= 4-√8 Can someone confirm

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