Waste less time on Facebook — follow Brilliant.
×

Overlapping area given vertices

As stated in the title, is it possible to determine the overlapping area of polygons given the coordinates of the vertices of each polygon?

Note by Lolly Lau
1 year, 4 months ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

Well as i see it, it only involves finding the area enclosed by a group of lines whose equations we know. The final area will also be a polygon whose vertices(coordinates) we know, hence its area .

Keshav Tiwari - 1 year, 4 months ago

Log in to reply

The group of lines do not define the actual overlapping area though. Say two polygons have zero overlapping area. You see where this is going?

Lolly Lau - 1 year, 4 months ago

Log in to reply

Okay... I get it now. Did you think of this while solving a problem? If so ,please share it .

Keshav Tiwari - 1 year, 4 months ago

Log in to reply

I thought of this while conceiving the 'SCAA Logo' problem.

Lolly Lau - 1 year, 4 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...