I think 8/π is right answer either it is square or rectangle. because in both case both diagonal will be same, because it is diameter of circle. So even by changing length and width of the rectangle parameter will be same in all case. and that can be find by assuming that rectangle as a square..

I took the rectangle as a square. If that's not the case, then the problem is lacking some information i guess.

If we consider the rectangle to be a square, then here goes the solution:
We have, \(\large \pi\times r^2=\large \frac{2}{\pi} \implies \boxed {r=\frac{\sqrt{2}}{\pi}} \)
Now, let the side of square be \(x\). Then \(\large 2\times x^2=\large \frac{8}{\pi^2} \implies x=\large \frac{2}{\pi}\)
This means the perimeter is \(\large 4\times \large \frac{2}{\pi}=\large \boxed {\boxed{\frac{8}{\pi}}} \)

I think many answers are possible. It's 8/π only when the rectangle is a square, as in a
rectangle other than the square the angle made by the two radii by either the length or breadth is not 90 degrees so we can't apply pythagoras theorem here.

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TopNewestComment deleted Apr 27, 2013

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k doesn't matter ...

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I think 8/π is right answer either it is square or rectangle. because in both case both diagonal will be same, because it is diameter of circle. So even by changing length and width of the rectangle parameter will be same in all case. and that can be find by assuming that rectangle as a square..

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its 8/pie.....i calculated so..

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how please explain

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I took the rectangle as a square. If that's not the case, then the problem is lacking some information i guess.

If we consider the rectangle to be a square, then here goes the solution: We have, \(\large \pi\times r^2=\large \frac{2}{\pi} \implies \boxed {r=\frac{\sqrt{2}}{\pi}} \) Now, let the side of square be \(x\). Then \(\large 2\times x^2=\large \frac{8}{\pi^2} \implies x=\large \frac{2}{\pi}\) This means the perimeter is \(\large 4\times \large \frac{2}{\pi}=\large \boxed {\boxed{\frac{8}{\pi}}} \)

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yeah \(\Large \frac{8}{\pi}\) is correct

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I think many answers are possible. It's 8/π only when the rectangle is a square, as in a rectangle other than the square the angle made by the two radii by either the length or breadth is not 90 degrees so we can't apply pythagoras theorem here.

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