I think 8/π is right answer either it is square or rectangle. because in both case both diagonal will be same, because it is diameter of circle. So even by changing length and width of the rectangle parameter will be same in all case. and that can be find by assuming that rectangle as a square..
–
Bharat Bhawsar
·
3 years, 4 months ago

Log in to reply

its 8/pie.....i calculated so..
–
Anurag Nayan
·
4 years, 2 months ago

@Google Face
–
I took the rectangle as a square. If that's not the case, then the problem is lacking some information i guess.

If we consider the rectangle to be a square, then here goes the solution:
We have, \(\large \pi\times r^2=\large \frac{2}{\pi} \implies \boxed {r=\frac{\sqrt{2}}{\pi}} \)
Now, let the side of square be \(x\). Then \(\large 2\times x^2=\large \frac{8}{\pi^2} \implies x=\large \frac{2}{\pi}\)
This means the perimeter is \(\large 4\times \large \frac{2}{\pi}=\large \boxed {\boxed{\frac{8}{\pi}}} \)
–
Vikram Waradpande
·
4 years, 2 months ago

@Vikram Waradpande
–
I think many answers are possible. It's 8/π only when the rectangle is a square, as in a
rectangle other than the square the angle made by the two radii by either the length or breadth is not 90 degrees so we can't apply pythagoras theorem here.
–
Bhargav Das
·
4 years, 2 months ago

## Comments

Sort by:

TopNewestLog in to reply

– Google Face · 4 years, 2 months ago

k doesn't matter ...Log in to reply

I think 8/π is right answer either it is square or rectangle. because in both case both diagonal will be same, because it is diameter of circle. So even by changing length and width of the rectangle parameter will be same in all case. and that can be find by assuming that rectangle as a square.. – Bharat Bhawsar · 3 years, 4 months ago

Log in to reply

its 8/pie.....i calculated so.. – Anurag Nayan · 4 years, 2 months ago

Log in to reply

– Google Face · 4 years, 2 months ago

how please explainLog in to reply

If we consider the rectangle to be a square, then here goes the solution: We have, \(\large \pi\times r^2=\large \frac{2}{\pi} \implies \boxed {r=\frac{\sqrt{2}}{\pi}} \) Now, let the side of square be \(x\). Then \(\large 2\times x^2=\large \frac{8}{\pi^2} \implies x=\large \frac{2}{\pi}\) This means the perimeter is \(\large 4\times \large \frac{2}{\pi}=\large \boxed {\boxed{\frac{8}{\pi}}} \) – Vikram Waradpande · 4 years, 2 months ago

Log in to reply

– Vikram Waradpande · 4 years, 2 months ago

yeah \(\Large \frac{8}{\pi}\) is correctLog in to reply

– Bhargav Das · 4 years, 2 months ago

I think many answers are possible. It's 8/π only when the rectangle is a square, as in a rectangle other than the square the angle made by the two radii by either the length or breadth is not 90 degrees so we can't apply pythagoras theorem here.Log in to reply

– Vikram Waradpande · 4 years, 2 months ago

Yeah I took the rectangle to be a square.Log in to reply