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permutations are permutations only

Haai brilliant members i am here to talk about how to find the no. of possible ways of arranging the letters of any word . i already gave a problem regarding this its too critical .

suppose there are 5 letters to be filled with vowels . we know that there are totally 5 vowels . in 1st blank there are 5 possibilities in which we can fill . in 2nd blank , we can fill in 4 possibilities because already we used a vowel to fill the 1st blank . same as 3rd with 3 vowels and 4th with 2 vowels and 5th with 1 vowel . so the total no. of ways is 5 X 4 X 3 X 2 X 1 = 5! = 120

there is also a formula for this it is n!/n - r where n stands for no. of letters and r stands for no. of blanks available to fill the letters . answer for the above example using formula is 5!/(5 - 5)! =120/1 = 120 [since 0! = 1] hope you understand see you next time like this for suggestions and doubts contact me at my e-mail "sudokusubramanyam@gmail.com"

Note by Sudoku Subbu
2 years ago

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Nice.Thanks for you'r help.Even though I had known these already, It will be useful for me in the future Vishal S · 2 years ago

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@Vishal S you are not upto my state : bose einstien condense state i want a note about bose einstien condense state and plasma state can you give it vishal if you are vishal give me that one Sudoku Subbu · 2 years ago

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@Sudoku Subbu Okay. I'l give it in my note Vishal S · 2 years ago

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vishal give a reply now Sudoku Subbu · 2 years ago

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@Sudoku Subbu Please be mindful of your language on Brilliant. I have deleted your comment with offensive language. Calvin Lin Staff · 2 years ago

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@Calvin Lin sorry for you . forgive me . Sudoku Subbu · 2 years ago

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