@A E
–
Ya I got kv^2/2.it will be misleading for many I guess to mark kv^2.but if the part held goes a distance of vt then the part coming to motion will have a length of vt/2.its quite apparent and easy to analyse if the part held goes vt then the part that will be available to come to motion must be vt as length is conserved but this appears in the curl with 2 half length of (vt/2)each!!!so now we can use f=vdm/dt =vd(kvt/2)/dt=kv^2/2.

@A E
–
are mein to kuch bi nhi hue yaar , bhai hoga to yeh Q dubara mat poocheyo plz , meri padai ke mamle mein bezzati kr liya kr besak :) P.S i hardly studied today :P

shit ! i wrote it on paper and clicked pic to show you , displaced the power cord a little and boom , computer off. after then solved 4 level 5's and wrote their solution , upvote them too :P le dekh le

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## Comments

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TopNewestThe best part is I could perform this at home after solving.just take a slinky tie its end and make a curl and move it.you will get it.

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bas bi kar pura lecture lagaega kya ? :P

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Don't mind your handwriting isn't good.although legible

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ok ....thanks for help!!!

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Oye @A E

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kidhar hai bhai ?

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Ghar pe.

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Yes....reading the solution

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shit ! i wrote it on paper and clicked pic to show you , displaced the power cord a little and boom , computer off. after then solved 4 level 5's and wrote their solution , upvote them too :P le dekh le

samaj aa gya ?

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How to solve this? : momentum change= force :)

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But using this answer comes as hv^2

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which one is given as answer ?

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ha! did it a long time ago ! :P

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I told you ....you are awesome in physics

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@Spandan Senapati @shubham dhull. @Swapnil Das

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Hey, that was a nice question!

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Thanks.....try previous years inpho papers they are awesome.

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