Waste less time on Facebook — follow Brilliant.
×

Physics doubt!

How to solve this? I understand that we need to use force as vdm/dt but the answer doesn't match?

Note by A E
9 months ago

No vote yet
1 vote

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

The best part is I could perform this at home after solving.just take a slinky tie its end and make a curl and move it.you will get it.

Spandan Senapati - 9 months ago

Log in to reply

bas bi kar pura lecture lagaega kya ? :P

Brilliant Member - 9 months ago

Log in to reply

Don't mind your handwriting isn't good.although legible

Spandan Senapati - 9 months ago

Log in to reply

@Spandan Senapati achha thik hai. :(

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member Ab handwriting pe fight mat karo bhaiyon...

A E - 9 months ago

Log in to reply

@A E maine to kuch kaha hi ni ! , koi aur question de na yaar :)

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member Ruk kaal Deta hoon a hi mai abhi sone jaa raha hoon !!!!

A E - 9 months ago

Log in to reply

@A E kai saarre laio , waisse toh mujhe module bhi shuru kar ne hai , phir bhi :)

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member Yaa.... sure

A E - 9 months ago

Log in to reply

@A E l'm the only one from my center not to even start doing my coaching modules while others have finished it :\

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member Modules se accha hai kuch achhe books karna ,uske bad modules relatively easy lagenge....

A E - 9 months ago

Log in to reply

@A E abe time kaha hai ? ab to cbse aur 2 ko mains :!

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member Bas Chem hi bacha hoga na ?

A E - 9 months ago

Log in to reply

@A E sare subject , mera bura haal hai ::

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member OK then all the best.....be positive mains accha hoga aur adv bhi

A E - 9 months ago

Log in to reply

@A E thnx bhai , as long as bhais like you r around me no mains-advance can stop me :) (hopefully:P)

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member Yes ....study hard you will rock both the exams. Good night.

A E - 9 months ago

Log in to reply

@A E yep gd........tc :D

Brilliant Member - 9 months ago

Log in to reply

ok ....thanks for help!!!

A E - 9 months ago

Log in to reply

Oye @A E

Brilliant Member - 9 months ago

Log in to reply

kidhar hai bhai ?

Brilliant Member - 9 months ago

Log in to reply

Ghar pe.

A E - 9 months ago

Log in to reply

@A E mera net slow hai :P pehle likha tha

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member yeh question INPHO 2009 ka tha .

A E - 9 months ago

Log in to reply

@A E Ya I got kv^2/2.it will be misleading for many I guess to mark kv^2.but if the part held goes a distance of vt then the part coming to motion will have a length of vt/2.its quite apparent and easy to analyse if the part held goes vt then the part that will be available to come to motion must be vt as length is conserved but this appears in the curl with 2 half length of (vt/2)each!!!so now we can use f=vdm/dt =vd(kvt/2)/dt=kv^2/2.

Spandan Senapati - 9 months ago

Log in to reply

@Spandan Senapati yaa ......great observation.

A E - 9 months ago

Log in to reply

@A E And only one part of the curl will be in motion as the other will be with the ground itself.(so rest)☺☺

Spandan Senapati - 9 months ago

Log in to reply

@A E oh ! samaj aa gya ke ?

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member haan aa gya.....itna physics kaise aata hai bhai?????

A E - 9 months ago

Log in to reply

@A E are mein to kuch bi nhi hue yaar , bhai hoga to yeh Q dubara mat poocheyo plz , meri padai ke mamle mein bezzati kr liya kr besak :) P.S i hardly studied today :P

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member yeh 2nd solution mein 1/2 mv^2 ko kisse equate kiya hai....dikhai nahi de raha ?

A E - 9 months ago

Log in to reply

@A E F*l ( force *length )

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member achha thik hai..

A E - 9 months ago

Log in to reply

@Brilliant Member online whole day :(

Brilliant Member - 9 months ago

Log in to reply

Yes....reading the solution

A E - 9 months ago

Log in to reply

shit ! i wrote it on paper and clicked pic to show you , displaced the power cord a little and boom , computer off. after then solved 4 level 5's and wrote their solution , upvote them too :P le dekh le

samaj aa gya ?

samaj aa gya ?

Brilliant Member - 9 months ago

Log in to reply

How to solve this? : momentum change= force :)

Brilliant Member - 9 months ago

Log in to reply

But using this answer comes as hv^2

A E - 9 months ago

Log in to reply

which one is given as answer ?

Brilliant Member - 9 months ago

Log in to reply

@Brilliant Member hv^2/2

A E - 9 months ago

Log in to reply

ha! did it a long time ago ! :P

Brilliant Member - 9 months ago

Log in to reply

I told you ....you are awesome in physics

A E - 9 months ago

Log in to reply

@Spandan Senapati @shubham dhull. @Swapnil Das

A E - 9 months ago

Log in to reply

Hey, that was a nice question!

Swapnil Das - 8 months, 4 weeks ago

Log in to reply

Thanks.....try previous years inpho papers they are awesome.

A E - 8 months, 4 weeks ago

Log in to reply

@A E Yup, they are.

Swapnil Das - 8 months, 4 weeks ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...