The current in a conductor varies as follows: during the first 8 sec there is a linear change from zero to 4 amp; during the next 15 sec the current is constant at 4 amp; during a third period of 20 sec the current decreases linearly to 3 amp. Determine (a) the total charge transferred in the elapsed time of 43 sec, (b) the average current

## Comments

Sort by:

TopNewesttry drawing the graph of current v/s time. And use the concept the area enclosed by graph with time axis shall give you total charge flown (i.e Ans Part (a) ). Once you've calculated the total charge flown through the conductor, The avg. current is = Total Charge flown/ Total time taken – Rahul Nahata · 3 years, 9 months ago

Log in to reply

– Juverne Arjoy Carandang · 3 years, 9 months ago

oh thankyou so much :)Log in to reply

The answer must be (a)146C (b)3.395A – Maharnab Mitra · 3 years, 9 months ago

Log in to reply

– Juverne Arjoy Carandang · 3 years, 9 months ago

Can you explain to me, how did you get that answers? Thankyou :)Log in to reply

how ? explain more plss – Al Jade Abello · 3 years, 9 months ago

Log in to reply

– Juverne Arjoy Carandang · 3 years, 9 months ago

hey, this is all about on basic electrical circuits..Log in to reply