A wire of mass \(100 g\) is carrying a current of \(2 A\) towards increasing \(x\) in the form of \(y=x^2 (-2m \leq x \leq +2m)\). This wire is placed in a magnetic field \(\vec{B} = -0.02 \hat{k}\) tesla. The acceleration of the wire (in \(m/s^2\)) is

\((a)\) \(-1.6 \hat{j}\)

\((b)\) \(-3.2 \hat{j}\)

\((c)\) \(1.6 \hat{j}\)

\((d)\) \(0\)

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TopNewestgot it!!! – Advitiya Brijesh · 4 years, 4 months ago

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– Ramon Vicente Marquez · 4 years, 4 months ago

C. The magnetic field is uniform and cross product is distributive. Thus, the wire is equivalent to a 4 m wire carrying a 2 A current to the right.Log in to reply

– Raja Metronetizen · 4 years, 4 months ago

then please elaborate.....i got stuck to it myself....Log in to reply