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\(\pi\) Algorithm

I took a circle and a sector with \(\theta\) very less about \(\frac { 1 }{ { 10 }^{ 20 } }\).

Using sine formula

\(\frac { a }{ { sinx } } \quad =\quad \frac { r }{ sinb } \) ........................ (1)

Here b = \(90-\frac { x }{ 2 } \)

So sin b = cos \(\frac { b }{ 2 }\)

Equating in equation (1) I got

\(\pi\) = \(sin\frac { x }{ 2 } \cdot \frac { 360 }{ x }\)

and putting the above value of \(\frac { 1 }{ { 10 }^{ 20 } }\) for \(x\) I Found

\(\pi\) = 3.1415926535897932384626433832795

Please Reply If any STAFF member see this and loved this.

© Anand Raj

Note by Anand Raj
3 years, 4 months ago

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