Well, the outcome of the experiment can depend on several things. First thing I immediately noticed is that even when the ground has friction, the answer is indeterminable. it depends on how much friction there is and what angle the plank is to the floor. So what I think the answer to this question is \(\boxed{\text{indeterminable}}\).

If you consider the torque around point A (where the plank touch the wall), you'll see there is only the torque of P (plank weight) -> it will fall due to the unbalance

I guess it all depends upon the mass of plank and the coefficient of friction of the rough wall. Considering there is no friction on the floor, the force of friction on the wall must be greater than the weight of the plank due to gravity. If it happens, the plank will not fall,else,IT WILL.

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TopNewestWell, the outcome of the experiment can depend on several things. First thing I immediately noticed is that even when the ground has friction, the answer is indeterminable. it depends on how much friction there is and what angle the plank is to the floor. So what I think the answer to this question is \(\boxed{\text{indeterminable}}\).

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If you consider the torque around point A (where the plank touch the wall), you'll see there is only the torque of P (plank weight) -> it will fall due to the unbalance

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A similar problem is in HC Verma

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I guess it all depends upon the mass of plank and the coefficient of friction of the rough wall. Considering there is no friction on the floor, the force of friction on the wall must be greater than the weight of the plank due to gravity. If it happens, the plank will not fall,else,IT WILL.

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Apply the concept of torque.

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