\(\large Sin \theta+Sin^{2} \theta+Sin^{3} \theta=1\)
Find the value of
\(\large Cos^{6} \theta-4Cos^{4} \theta+8Cos^{2} \theta\)
Thanks!!
\(\large Sin \theta+Sin^{2} \theta+Sin^{3} \theta=1\)
Find the value of
\(\large Cos^{6} \theta-4Cos^{4} \theta+8Cos^{2} \theta\)
Thanks!!
Note by
Naitik Sanghavi
1 year, 8 months ago
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Top NewestThere's no "nice" solution. You can determine the value of \(\cos^2\theta\) by squaring the first equation and solve the quartic equation, but the final value does not have a nice form. – Pi Han Goh · 1 year, 8 months ago
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I'm sorry !I think the question was wrongly printed in my book!! I searched and found that its Cos^6theta-4Cos⁴+8Cos²!!
Thanks for your reply! – Naitik Sanghavi · 1 year, 8 months ago
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