$$\large Sin \theta+Sin^{2} \theta+Sin^{3} \theta=1$$

Find the value of

$$\large Cos^{6} \theta-4Cos^{4} \theta+8Cos^{2} \theta$$

Thanks!!

Note by Naitik Sanghavi
2 years, 7 months ago

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There's no "nice" solution. You can determine the value of $$\cos^2\theta$$ by squaring the first equation and solve the quartic equation, but the final value does not have a nice form.

- 2 years, 7 months ago

I'm sorry !I think the question was wrongly printed in my book!! I searched and found that its Cos^6theta-4Cos⁴+8Cos²!!