Waste less time on Facebook — follow Brilliant.
×

please anyone help me....

a number consist of two digit whose sum is 8. if 18 is added to the number the digits change their places . find the number

Note by Pooja Arora
4 years, 7 months ago

No vote yet
2 votes

  Easy Math Editor

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 \( 2 \times 3 \)
2^{34} \( 2^{34} \)
a_{i-1} \( a_{i-1} \)
\frac{2}{3} \( \frac{2}{3} \)
\sqrt{2} \( \sqrt{2} \)
\sum_{i=1}^3 \( \sum_{i=1}^3 \)
\sin \theta \( \sin \theta \)
\boxed{123} \( \boxed{123} \)

Comments

Sort by:

Top Newest

The number is 35.

Siddharth Kumar - 4 years, 7 months ago

Log in to reply

how??

Pooja Arora - 4 years, 7 months ago

Log in to reply

pls give me step by step procedure...

Pooja Arora - 4 years, 7 months ago

Log in to reply

@Pooja Arora \(x\) is the digit at tens place and \(y\) at units place.

\(x+y=8\)

\(10x+y+18=10y+x\)

Just solve these equations.

Aditya Parson - 4 years, 7 months ago

Log in to reply

@Aditya Parson thanku so much.....

Pooja Arora - 4 years, 7 months ago

Log in to reply

@Aditya Parson agreed...:)

Riya Gupta - 4 years, 7 months ago

Log in to reply

@Pooja Arora find the pairs of one-digit numbers whose sum is 8: \( (1,7),(2,6),(3,5) \) then the possibilities are 17,26 and 35 by trial and error we get 35

Tan Li Xuan - 4 years, 7 months ago

Log in to reply

let the unit digit be x &tens digit be ythen original no.is10y +x. and 1st equation is x+y =8 and 2nd equation is 10y+x+18=10x+y then from eq.1 x=8-y substituting the value of x in 2nd equation 10y+8-y +18=10(8-y)+y 9y +26=80-10y+y 9y+26=80-9y 9y +9y=80-26 18y=54 y=3 x=8-3=5 no.=10*3+5 35

Nikhil Raj - 4 years, 7 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...