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please anyone help me....

a number consist of two digit whose sum is 8. if 18 is added to the number the digits change their places . find the number

Note by Pooja Arora
3 years, 9 months ago

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The number is 35. Siddharth Kumar · 3 years, 9 months ago

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@Siddharth Kumar how?? Pooja Arora · 3 years, 9 months ago

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@Pooja Arora pls give me step by step procedure... Pooja Arora · 3 years, 9 months ago

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@Pooja Arora \(x\) is the digit at tens place and \(y\) at units place.

\(x+y=8\)

\(10x+y+18=10y+x\)

Just solve these equations. Aditya Parson · 3 years, 9 months ago

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@Aditya Parson thanku so much..... Pooja Arora · 3 years, 9 months ago

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@Aditya Parson agreed...:) Riya Gupta · 3 years, 9 months ago

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@Pooja Arora find the pairs of one-digit numbers whose sum is 8: \( (1,7),(2,6),(3,5) \) then the possibilities are 17,26 and 35 by trial and error we get 35 Tan Li Xuan · 3 years, 9 months ago

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let the unit digit be x &tens digit be ythen original no.is10y +x. and 1st equation is x+y =8 and 2nd equation is 10y+x+18=10x+y then from eq.1 x=8-y substituting the value of x in 2nd equation 10y+8-y +18=10(8-y)+y 9y +26=80-10y+y 9y+26=80-9y 9y +9y=80-26 18y=54 y=3 x=8-3=5 no.=10*3+5 35 Nikhil Raj · 3 years, 9 months ago

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