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a number consist of two digit whose sum is 8. if 18 is added to the number the digits change their places . find the number

Note by Pooja Arora
4 years, 4 months ago

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The number is 35.

- 4 years, 4 months ago

how??

- 4 years, 4 months ago

pls give me step by step procedure...

- 4 years, 4 months ago

$$x$$ is the digit at tens place and $$y$$ at units place.

$$x+y=8$$

$$10x+y+18=10y+x$$

Just solve these equations.

- 4 years, 4 months ago

thanku so much.....

- 4 years, 4 months ago

agreed...:)

- 4 years, 4 months ago

find the pairs of one-digit numbers whose sum is 8: $$(1,7),(2,6),(3,5)$$ then the possibilities are 17,26 and 35 by trial and error we get 35

- 4 years, 4 months ago

let the unit digit be x &tens digit be ythen original no.is10y +x. and 1st equation is x+y =8 and 2nd equation is 10y+x+18=10x+y then from eq.1 x=8-y substituting the value of x in 2nd equation 10y+8-y +18=10(8-y)+y 9y +26=80-10y+y 9y+26=80-9y 9y +9y=80-26 18y=54 y=3 x=8-3=5 no.=10*3+5 35

- 4 years, 4 months ago