Waste less time on Facebook — follow Brilliant.
×

Please Explain

If \(x\leq3\), then find the interval between which the value of \( \dfrac{1}{x} \) lies.

Note by Sahba Hasan
8 months ago

No vote yet
1 vote

Comments

Sort by:

Top Newest

Suppose \( x > 0 \).
Then \( x \leq 3 \Rightarrow \frac{1}{x} \geq \frac{1}{3} \) (on dividing by x).
This means \(\frac{1}{x} \in [\frac{1}{3}, \infty)\).

If \( x < 0 \) then \(\frac{1}{x} \in (-\infty, 0)\). (Look at the graph!).
\(\frac{1}{x}\) is not defined at \( x = 0\).

Combining all this we have \(\frac{1}{x} \in (-\infty, 0)\cup [\frac{1}{3}, \infty)\). Ameya Daigavane · 8 months ago

Log in to reply

@Ameya Daigavane Thanks a lot... Sahba Hasan · 8 months ago

Log in to reply

×

Problem Loading...

Note Loading...

Set Loading...