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Please find the sum of series\(\frac { 1 }{ 1 } +\frac { 1 }{ 4 } \frac { 1 }{ 64 } +............................................till \infty \). Post solutions too

Note by Kandarp Singh 2 years, 6 months ago

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What's the next term in the series ?

I have a few options .

If it is \[ \dfrac{1}{3^{2}}\dfrac{1}{3^{3}}\]

Then the series is \(\zeta(5)\) . Look up Reimann Zeta function ,(sorry , I'm out of time so I can't provide u a link )

If it is \[\dfrac{1}{3^{2}}\dfrac{1}{{2.3}^{2}}\]

Then it will be \[\dfrac{1}{4}\zeta(4)\] .

Have I satisfactorily answered ur doubt . I gotta dash . I have mentioned a few of my friends , they'll surely help u out :D

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@Kartik Sharma , @Ishan Dasgupta Samarendra , @Krishna Ar , @Sharky Kesa \(\dots\)

Am I correct ?

Not sure, trying it now. @Kandarp Singh Look this up - it might help.

@Azhaghu Roopesh M See, this is one of the reasons I said you are the best person I know here. You always, always help others! \[\] @Pranjal Jain @Pratik Shastri @Samarpit Swain @Sandeep Bhardwaj Sir

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TopNewestWhat's the next term in the series ?

I have a few options .

If it is \[ \dfrac{1}{3^{2}}\dfrac{1}{3^{3}}\]

Then the series is \(\zeta(5)\) . Look up Reimann Zeta function ,(sorry , I'm out of time so I can't provide u a link )

If it is \[\dfrac{1}{3^{2}}\dfrac{1}{{2.3}^{2}}\]

Then it will be \[\dfrac{1}{4}\zeta(4)\] .

Have I satisfactorily answered ur doubt . I gotta dash . I have mentioned a few of my friends , they'll surely help u out :D

Log in to reply

@Kartik Sharma , @Ishan Dasgupta Samarendra , @Krishna Ar , @Sharky Kesa \(\dots\)

Am I correct ?

Log in to reply

Not sure, trying it now. @Kandarp Singh Look this up - it might help.

@Azhaghu Roopesh M See, this is one of the reasons I said you are the best person I know here. You always, always help others! \[\] @Pranjal Jain @Pratik Shastri @Samarpit Swain @Sandeep Bhardwaj Sir

Log in to reply