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Note by Raghav Rathi 1 year, 1 month ago

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Understand if you can – Prince Loomba · 1 year, 1 month ago

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Only 1 solution is possible

\(a=\sqrt{30}/3\)

\(b=\sqrt{30}/4\)

\(c=2\sqrt{30}/5\)

For positive a,b,c – Prince Loomba · 1 year, 1 month ago

@Prince Loomba – I think there are multiple solutions. I just tried it out with Desmos – Hung Woei Neoh · 1 year, 1 month ago

@Hung Woei Neoh – Are they all positive real numbers? – Prince Loomba · 1 year, 1 month ago

@Prince Loomba – You can have negative numbers – Hung Woei Neoh · 1 year, 1 month ago

@Hung Woei Neoh – I gave only positive – Prince Loomba · 1 year, 1 month ago

@Prince Loomba – can you please illustrate how did you find that solution.? – Raghav Rathi · 1 year, 1 month ago

Divide equations and then set up an inequality for the floor function? Not to sure though. – Ian Limarta · 1 year, 1 month ago

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TopNewestUnderstand if you can – Prince Loomba · 1 year, 1 month ago

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Only 1 solution is possible

\(a=\sqrt{30}/3\)

\(b=\sqrt{30}/4\)

\(c=2\sqrt{30}/5\)

For positive a,b,c – Prince Loomba · 1 year, 1 month ago

Log in to reply

– Hung Woei Neoh · 1 year, 1 month ago

I think there are multiple solutions. I just tried it out with DesmosLog in to reply

– Prince Loomba · 1 year, 1 month ago

Are they all positive real numbers?Log in to reply

– Hung Woei Neoh · 1 year, 1 month ago

You can have negative numbersLog in to reply

– Prince Loomba · 1 year, 1 month ago

I gave only positiveLog in to reply

– Raghav Rathi · 1 year, 1 month ago

can you please illustrate how did you find that solution.?Log in to reply

Divide equations and then set up an inequality for the floor function? Not to sure though. – Ian Limarta · 1 year, 1 month ago

Log in to reply