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Note by Raghav Rathi 7 months, 4 weeks ago

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Understand if you can – Prince Loomba · 7 months, 3 weeks ago

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Only 1 solution is possible

\(a=\sqrt{30}/3\)

\(b=\sqrt{30}/4\)

\(c=2\sqrt{30}/5\)

For positive a,b,c – Prince Loomba · 7 months, 3 weeks ago

@Prince Loomba – I think there are multiple solutions. I just tried it out with Desmos – Hung Woei Neoh · 7 months, 3 weeks ago

@Hung Woei Neoh – Are they all positive real numbers? – Prince Loomba · 7 months, 3 weeks ago

@Prince Loomba – You can have negative numbers – Hung Woei Neoh · 7 months, 3 weeks ago

@Hung Woei Neoh – I gave only positive – Prince Loomba · 7 months, 3 weeks ago

@Prince Loomba – can you please illustrate how did you find that solution.? – Raghav Rathi · 7 months, 3 weeks ago

Divide equations and then set up an inequality for the floor function? Not to sure though. – Ian Limarta · 7 months, 3 weeks ago

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TopNewestUnderstand if you can – Prince Loomba · 7 months, 3 weeks ago

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Only 1 solution is possible

\(a=\sqrt{30}/3\)

\(b=\sqrt{30}/4\)

\(c=2\sqrt{30}/5\)

For positive a,b,c – Prince Loomba · 7 months, 3 weeks ago

Log in to reply

– Hung Woei Neoh · 7 months, 3 weeks ago

I think there are multiple solutions. I just tried it out with DesmosLog in to reply

– Prince Loomba · 7 months, 3 weeks ago

Are they all positive real numbers?Log in to reply

– Hung Woei Neoh · 7 months, 3 weeks ago

You can have negative numbersLog in to reply

– Prince Loomba · 7 months, 3 weeks ago

I gave only positiveLog in to reply

– Raghav Rathi · 7 months, 3 weeks ago

can you please illustrate how did you find that solution.?Log in to reply

Divide equations and then set up an inequality for the floor function? Not to sure though. – Ian Limarta · 7 months, 3 weeks ago

Log in to reply