\(501 \times502 \times503 = (500+1)(500+2)(500+3) =500(500+2)(500+3) + (500(500+3)) +2(500) + 6\) .....when dividing by \(25\) the only term left out is \(6\) the remaining are evenly divisible by \(25\) ..therefore the remainder is \(\boxed{6}\).
–
Anik Mandal
·
1 year, 1 month ago

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TopNewest\(501 \times502 \times503 = (500+1)(500+2)(500+3) =500(500+2)(500+3) + (500(500+3)) +2(500) + 6\) .....when dividing by \(25\) the only term left out is \(6\) the remaining are evenly divisible by \(25\) ..therefore the remainder is \(\boxed{6}\). – Anik Mandal · 1 year, 1 month ago

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6 – Deepansh Jindal · 2 months, 4 weeks ago

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(500+1)X(500+2)X(500+3)=Multiple of 100+6 i.e. last 2 digits are 06. Therefore remainder when divided by 25 is 6. – Prince Loomba · 8 months ago

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6 – Prabhav Bansal · 1 year, 1 month ago

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6 – Faizan Khan · 1 year, 1 month ago

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6 – Lalitha Jyothi · 1 year, 1 month ago

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Check out Modular Arithmetic - Multiplication. – Calvin Lin Staff · 1 year, 1 month ago

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