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What is the remainder when 501 * 502 * 503 is divided by 25?

Note by Pramita Kastha 3 years ago

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\(501 \times502 \times503 = (500+1)(500+2)(500+3) =500(500+2)(500+3) + (500(500+3)) +2(500) + 6\) .....when dividing by \(25\) the only term left out is \(6\) the remaining are evenly divisible by \(25\) ..therefore the remainder is \(\boxed{6}\).

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6

(500+1)X(500+2)X(500+3)=Multiple of 100+6 i.e. last 2 digits are 06. Therefore remainder when divided by 25 is 6.

Check out Modular Arithmetic - Multiplication.

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## Comments

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TopNewest\(501 \times502 \times503 = (500+1)(500+2)(500+3) =500(500+2)(500+3) + (500(500+3)) +2(500) + 6\) .....when dividing by \(25\) the only term left out is \(6\) the remaining are evenly divisible by \(25\) ..therefore the remainder is \(\boxed{6}\).

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6

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(500+1)X(500+2)X(500+3)=Multiple of 100+6 i.e. last 2 digits are 06. Therefore remainder when divided by 25 is 6.

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6

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6

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6

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Check out Modular Arithmetic - Multiplication.

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